Php 如何在纬度和经度的帮助下找到20公里以内的用户
我必须根据乘客lat和日志查找20公里内的所有驾驶员 我有下面两张驾驶员和乘客表。Php 如何在纬度和经度的帮助下找到20公里以内的用户,php,mysql,json,Php,Mysql,Json,我必须根据乘客lat和日志查找20公里内的所有驾驶员 我有下面两张驾驶员和乘客表。 乘客\u idpassenger\u姓名乘客\u latpassenger\u日志 1 David123.0755.03 2 Sunilxyz.pq abc.7 和驱动程序表 驱动程序\u ID驱动程序\u名称驱动程序\u车床驱动程序\u日志 1 Anil123.0755.03 2 Jamisxyz.pq abc.7 现在我有了输入参数passenger_lat和passenger_log。基于此
乘客\u idpassenger\u姓名乘客\u latpassenger\u日志
1 David123.0755.03
2 Sunilxyz.pq abc.7
和驱动程序表
驱动程序\u ID驱动程序\u名称驱动程序\u车床驱动程序\u日志
1 Anil123.0755.03
2 Jamisxyz.pq abc.7
现在我有了输入参数passenger_lat和passenger_log。基于此,我必须返回20公里内的所有驾驶员详细信息
SELECT *, ( 6371 * acos( cos( radians({$lat}) ) * cos( radians( lat ) ) * cos( radians( lng ) - radians({$lng}) ) + sin( radians({$lat}) ) * sin( radians( lat ) ) ) ) AS distance FROM positions HAVING distance <= {$radius} ORDER BY distance ASC
SELECT*,(6371*acos(cos(radians({$lat}))*cos(radians(lat))*cos(radians(lng)-radians({$lng}))+sin(radians({$lat}))*sin(radians(lat)))作为与具有距离的位置之间的距离StackOverflow不是软件写入服务。请展示你自己的努力和你被困的地方。是的,先生。使用以下代码,如SELECT*,(6371*acos(cos(弧度({$lat}))*cos(弧度(lat
)*cos(弧度(lng
)-radians({$lng}))+sin(弧度({$lat}))*sin(弧度(lat
))作为距离位置的距离
要从本地主机或服务器测试此代码,只需使用localhost/filename.php?action=find\u driver&user\u latitude=some数值和user\u longitude=some数值
class distance
{
public function all_user()
{
$query="select * from driver_user";
$query_run= mysql_query($query);
// $row= mysql_fetch_assoc($query_run);
while($row= mysql_fetch_assoc($query_run))
{
$dis= $this->call_distance(10,20,$row['current_latitude'],$row['current_longitude']);
}
}
public function call_distance($lat1, $lon1, $lat2, $lon2) {
$theta = $lon1 - $lon2;
$dist = sin(deg2rad($lat1)) * sin(deg2rad($lat2)) + cos(deg2rad($lat1)) * cos(deg2rad($lat2)) * cos(deg2rad($theta));
$dist = acos($dist);
$dist = rad2deg($dist);
$miles = $dist * 60 * 1.1515;
return ($miles * 1.609344);
}
}
$distance=new distance();
$distance->all_user();
<?php
class driver_service
{
public function find_driver($data)
{
$driver_details=array();
$driver_detail=array();
$query="select driver_user_id,first_name,last_name,phone_no,cpf_no,driver_email_id,driver_image,current_latitude,current_longitude from driver_user";
$query_run= mysql_query($query);
// $row= mysql_fetch_assoc($query_run);
while($row= mysql_fetch_assoc($query_run))
{
$driver=array();
$dis= $this->call_distance($data['user_latitude'],$data['user_longitude'],$row['current_latitude'],$row['current_longitude']);
if($dis<=50)
{
$driver['driver_details']=$row;
$driver_detail[]=$driver;
}
}
if(empty($driver_detail))
{
$driver_details['status']="2~there is no driver between 20 kms";
}
else{
$driver_details['status']="1~success";
$driver_details['details']=$driver_detail;
}
echo json_encode($driver_details);
}
public function call_distance($lat1, $lon1, $lat2, $lon2) {
$theta = $lon1 - $lon2;
$dist = sin(deg2rad($lat1)) * sin(deg2rad($lat2)) + cos(deg2rad($lat1)) * cos(deg2rad($lat2)) * cos(deg2rad($theta));
$dist = acos($dist);
$dist = rad2deg($dist);
$miles = $dist * 60 * 1.1515;
return ($miles * 1.609344);
}
}
$driver_service=new driver_service();
if($_REQUEST['action'] == 'find_driver')
{
$driver_service->find_driver($_REQUEST);
}