Php 对特定键使用相同值的数组索引求和

我有以下数组：

[0] => Array

    (
        [id] => 1
        [uid] => 50
        [sum1] => 1
        [sum2] => 2
       

    )

[1] => Array

    (
        [id] => 2
        [uid] => 50
        [sum1] => 2
        [sum2] => 4
       

    )
[2] => Array

    (
        [id] => 3
        [uid] => 51
        [sum1] => 3
        [sum2] => 5
       

    )

正如您所看到的，在某些索引上，[uid]是相同的。数组的长度和数据是动态的。 我需要做的是合并具有相同[uid]值的索引，并对其他键的值求和：

[0] => Array

    (
        [id] => 2
        [uid] => 50
        [sum1] => 3
        [sum2] => 6
       

    )
[1] => Array

    (
        [id] => 3
        [uid] => 51
        [sum1] => 3
        [sum2] => 5
       

    )

但就我个人而言，我不知道该怎么做

---

感谢您的帮助

你可以这样做

<?php
$mainArray = [ 
    0 => Array
    (
        'id' => 1,
        'uid' => 50,
        'sum1' => 1,
        'sum2' => 2
    ),
    1 => Array
    (
        'id' => 2,
        'uid' => 50,
        'sum1' => 2,
        'sum2' => 4
    ),
    2 => Array
    (
        'id' => 3,
        'uid' => 51,
        'sum1' => 3,
        'sum2' => 5
    )
];
$newArray=[];
foreach ($mainArray as $value) {
    if(!array_key_exists($value['uid'], $newArray)){
        // Store first time
        $newArray[$value['uid']] = $value;
    }else{
        // Already exist, then sum and replace it
        $newArray[$value['uid']]['id'] = $value['id'];
        $newArray[$value['uid']]['sum1'] += $value['sum1'];// Sum with previous value
        $newArray[$value['uid']]['sum2'] += $value['sum2'];// Sum with previous value
    }
}
$newArray = array_values($newArray);// Reset indexes, Start the array index with zero
print_r($newArray);// To see the output

---

我想你是对的。实际上，我用类似的方法解决了这个问题：

$sumArray = Array();
foreach ($array1 as $item){

        if(isset($sumArray[$item['uid']])){          
          $sumArray[$item['idPartener']]['sum1'] += $item['sum1'];
          $sumArray[$item['idPartener']]['sum2'] += $item['sum2'];

        }else{          
          $sumArray[$item['uid']] = Array(
            'id' => $item['id'],             
            'sum1' => $item['sum1'],
            'sum2' => $item['sum2'] ,
          );
        }

    }

---

谢谢大家的帮助

这回答了你的问题吗？创建一个新数组，在原始数组上迭代，为每个项目检查是否存在具有相同uid的对象（使用数组列和数组搜索）。。。如果存在增量值，则附加。不难。实际上，B001并不难，因为在这个例子中，所有的idex都要求和，或者在我的例子中，我只需要求和匹配的键。@SalmanA，这是个好主意。我会尽力实现这一点。谢谢

$sumArray = Array();
foreach ($array1 as $item){

        if(isset($sumArray[$item['uid']])){          
          $sumArray[$item['idPartener']]['sum1'] += $item['sum1'];
          $sumArray[$item['idPartener']]['sum2'] += $item['sum2'];

        }else{          
          $sumArray[$item['uid']] = Array(
            'id' => $item['id'],             
            'sum1' => $item['sum1'],
            'sum2' => $item['sum2'] ,
          );
        }

    }