Php 如何在查询Laravel雄辩的结果时使用多个参数
我通过一个Laravel雄辩的控制器查询DB帖子,我想先过滤帖子,然后分页Php 如何在查询Laravel雄辩的结果时使用多个参数,php,laravel,eloquent,Php,Laravel,Eloquent,我通过一个Laravel雄辩的控制器查询DB帖子,我想先过滤帖子,然后分页 $filter = ['author_id' => $id, 'status' => 'live', 'type' => $type]; $posts = Post::where($filter)->orderBy('id','desc')->get(); $posts = Post::paginate(1, ['*'], 'page', $page); return $posts; 当
$filter = ['author_id' => $id, 'status' => 'live', 'type' => $type];
$posts = Post::where($filter)->orderBy('id','desc')->get();
$posts = Post::paginate(1, ['*'], 'page', $page);
return $posts;
当然,目前它只会分页。我如何组合这两个$posts
,以便对筛选结果进行分页
谢谢 只需将以下方法链接起来即可:
$posts = Post::where($filter)
->orderBy('id','desc')
->paginate(1, ['*'], 'page', $page);
只需将以下方法链接起来即可:
$posts = Post::where($filter)
->orderBy('id','desc')
->paginate(1, ['*'], 'page', $page);
您还可以像这样简化解决方案,这将变得更加灵活
$filter = ['author_id' => $id, 'status' => 'live', 'type' => $type];
$posts = new Post();
$posts = $posts->where($filter);
$posts = $posts->orderBy('id','desc');
$posts = $posts->paginate(1, ['*'], 'page', $page);
return $posts;
您还可以像这样简化解决方案,这将变得更加灵活
$filter = ['author_id' => $id, 'status' => 'live', 'type' => $type];
$posts = new Post();
$posts = $posts->where($filter);
$posts = $posts->orderBy('id','desc');
$posts = $posts->paginate(1, ['*'], 'page', $page);
return $posts;
杰出的现在说得通了-认为每个都需要
:
。太棒了!现在有意义了-认为每个都需要:
。