Php 将复杂对象图序列化为XML并返回 问题
我有以下对象图:Php 将复杂对象图序列化为XML并返回 问题,php,symfony,serialization,xml-serialization,symfony-2.7,Php,Symfony,Serialization,Xml Serialization,Symfony 2.7,我有以下对象图: AppBundle\Controller\Person Object ( [name:AppBundle\Controller\Person:private] => Person Name [age:AppBundle\Controller\Person:private] => 10 [phones:AppBundle\Controller\Person:private] => Array ( [
AppBundle\Controller\Person Object
(
[name:AppBundle\Controller\Person:private] => Person Name
[age:AppBundle\Controller\Person:private] => 10
[phones:AppBundle\Controller\Person:private] => Array
(
[0] => AppBundle\Controller\Telephone Object
(
[phone:AppBundle\Controller\Telephone:private] => 221-16-78
)
[1] => AppBundle\Controller\Telephone Object
(
[phone:AppBundle\Controller\Telephone:private] => 221-16-78
)
)
)
以及使用控制器中的以下代码进行序列化:
$s = $this->get("serializer")->serialize($person, 'xml');
这给了我以下的结果:
<response>
<name>Person Name</name>
<age>10</age>
<phones>
<phone>221-16-78</phone>
</phones>
<phones>
<phone>221-16-78</phone>
</phones>
</response>
正在返回以下内容:
AppBundle\Controller\Person Object
(
[name:AppBundle\Controller\Person:private] => Person Name
[age:AppBundle\Controller\Person:private] => 10
[phones:AppBundle\Controller\Person:private] => Array
(
[0] => Array
(
[phone] => 221-16-78
)
[1] => Array
(
[phone] => 221-16-78
)
)
)
问题:
首先,是否有如下方式接收xml:
<response>
<name>Person Name</name>
<age>10</age>
<phones>
<telephone>
<phone>221-16-78</phone>
</telephone>
<telephone>
<phone>221-16-78</phone>
</telephone>
</phones>
</response>
<?php
namespace AppBundle\Controller;
use JMS\Serializer\Annotation\Type;
use JMS\Serializer\Annotation\XmlList;
class Person {
/**
* @Type("string")
*/
private $name;
/**
* @Type("integer")
*/
private $age;
/**
* @Type("array<AppBundle\Controller\Telephone>")
* @XmlList(entry = "telephone")
*/
private $phones;
public function getName() {
return $this->name;
}
public function getAge() {
return $this->age;
}
public function getPhones() {
return $this->phones;
}
public function setName($name) {
$this->name = $name;
}
public function setAge($age) {
$this->age = $age;
}
public function setPhones($phones) {
$this->phones = $phones;
}
}
<?php
namespace AppBundle\Controller;
use JMS\Serializer\Annotation\Type;
class Telephone {
/**
* @Type("string")
*/
private $phone;
public function getPhone() {
return $this->phone;
}
public function setPhone($phone) {
$this->phone = $phone;
}
}
和我的控制器方法:
/**
* @Route("/", name="homepage")
*/
public function indexAction(Request $request)
{
$phone1 = new Telephone();
$phone1->setPhone("221-16-78");
$phone2 = new Telephone();
$phone2->setPhone("221-16-78");
$person = new Person();
$person->setName("Person Name");
$person->setAge(10);
$person->setPhones(array($phone1, $phone2));
print_r($person);
$s = $this->get("serializer")->serialize($person, 'xml');
$p = $this->get("serializer")->deserialize($s, 'AppBundle\Controller\Person', 'xml');
print_r($p);
}
使用JMS序列化程序的解决方案
通过使用注释(基本上是类型和列表细节)向序列化程序提供一些提示,我能够用JMS序列化程序解决这个问题,如下所示:
<response>
<name>Person Name</name>
<age>10</age>
<phones>
<telephone>
<phone>221-16-78</phone>
</telephone>
<telephone>
<phone>221-16-78</phone>
</telephone>
</phones>
</response>
<?php
namespace AppBundle\Controller;
use JMS\Serializer\Annotation\Type;
use JMS\Serializer\Annotation\XmlList;
class Person {
/**
* @Type("string")
*/
private $name;
/**
* @Type("integer")
*/
private $age;
/**
* @Type("array<AppBundle\Controller\Telephone>")
* @XmlList(entry = "telephone")
*/
private $phones;
public function getName() {
return $this->name;
}
public function getAge() {
return $this->age;
}
public function getPhones() {
return $this->phones;
}
public function setName($name) {
$this->name = $name;
}
public function setAge($age) {
$this->age = $age;
}
public function setPhones($phones) {
$this->phones = $phones;
}
}
<?php
namespace AppBundle\Controller;
use JMS\Serializer\Annotation\Type;
class Telephone {
/**
* @Type("string")
*/
private $phone;
public function getPhone() {
return $this->phone;
}
public function setPhone($phone) {
$this->phone = $phone;
}
}
名称;
}
公共函数getAge(){
返回$this->age;
}
公共函数getPhones(){
返回$this->phones;
}
公共函数setName($name){
$this->name=$name;
}
公共功能设置($age){
$this->age=$age;
}
公共功能手机($phones){
$this->phones=$phones;
}
}
据我所知,当您执行$this->get('serializer')
时,您将获得。我并不完全熟悉它(你会在一个勾中看到原因),但他们的文档确实强调了如何只针对序列化
对于您似乎正在寻找的对序列化视图的控制类型,我强烈建议(和)通过注释或外部配置对输出进行更细粒度的控制。在您的情况下,请执行以下操作:
use JMS\Serializer\Annotation as Serializer;
class Person
{
/**
* @Serializer\Type("array<Telephone>")
*/
private $phones;
使用JMS\Serializer\Annotation作为序列化程序;
班主任
{
/**
*@Serializer\Type(“数组”)
*/
私人电话;
可能足以获得您想要的双向序列化。谢谢您的回答,事实上它使用JMS序列化工作,但如果无法解决此问题,则对symfony2序列化程序感到好奇。在许多情况下,Symfony序列化程序是完全可用的,特别是在您仅进行序列化的情况下(而不是反序列化)对象-即通过API发送JSON。但据我所知,没有办法以JMS序列化程序允许的方式使用它进行复杂的转换,而这正是让示例正常工作所需要的。