如何通过PHP将图像上载到Azure存储？

我正试图通过用PHP构建的API将图像上传到blob存储中

目前我有这个，base64字符串是通过JSON Post发送的

//The base 64 string
$displayPictureBase64 = $this->ValidateParameter('DisplayPicture', $this->param, STRING);
//Decode it to byte array.
$displayPicture[] = base64_decode($displayPictureBase64);
//Name of the blob
$blobName = "MyBlobName";

//New BlobStorage class.
$blob = new BlobStorage;
$blob->AddBlob('user-display-pictures', $blobName, $displayPicture);

这将调用函数AddBlob

public function AddBlob($containerName, $fileName, $fileToUpload)
{
//Upload blob
$this->blobClient->createBlockBlob($containerName, $fileName, $fileToUpload);
}

（顺便说一句，我有blobClient的凭据，只是为了节省不必要的空间而没有在这里包含它。）

我遇到的问题是，函数blobClient->createBlockBlob接受这些参数

所以我的问题是，我发送的第三个参数是array类型的，但根据这一点，它应该是string。 这是我得到的PHP错误

PHP致命错误：未捕获InvalidArgumentException:无效的资源类型：D:\home\vendor\guzzlehttp\psr7\src\functions中的数组。PHP:116

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如何将图像作为字符串上载到blob存储？上的仅显示如何上载文本文件，而不是图像文件。谢谢

我通过以下操作修复了它

//The base 64 string
$displayPictureBase64 = $this->ValidateParameter('DisplayPicture', $this->param, STRING);

//Convert the file to stream
$fileToUpload = fopen('data:image/jpeg;base64,' . $displayPictureBase64,'r');
//Name of the blob
$blobName = "MyBlobName";

//New BlobStorage class.
$blob = new BlobStorage;
$blob->AddBlob('user-display-pictures', $blobName, $fileToUpload);

//The base 64 string
$displayPictureBase64 = $this->ValidateParameter('DisplayPicture', $this->param, STRING);

//Convert the file to stream
$fileToUpload = fopen('data:image/jpeg;base64,' . $displayPictureBase64,'r');
//Name of the blob
$blobName = "MyBlobName";

//New BlobStorage class.
$blob = new BlobStorage;
$blob->AddBlob('user-display-pictures', $blobName, $fileToUpload);