Php MySQL多表中多行的总和

我试图从两个不同的表中获取多行的总和，但结果会返回多行

我需要根据报价单id获取报价单\项目\金额组和发票\项目\金额组的总和，如果我查询未付款报价单，我需要获取SUMPOICE 这是我的样品表

table client_project_id
+-------------------+-----------+----------------------+
| client_project_id | client_id | client_project_title |
+-------------------+-----------+----------------------+
|         23        |     5     |        Project 1     |
|         17        |     9     |        Project 2     |
|         54        |     7     |        Project 3     |
+-------------------+-----------+----------------------+

table quotation
+--------------+-------------------+------------------+
| quotation_id | client_project_id | quotation_number |
+--------------+-------------------+------------------+
|       1      |          23       |   Q/01/2020/001  |
|       2      |          17       |   Q/01/2020/002  |
|       3      |          54       |   Q/01/2020/003  |
+--------------+-------------------+------------------+

table quotation_item
+-------------------+--------------+-----------------------+
| quotation_item_id | quotation_id | quotation_item_amount |
+-------------------+--------------+-----------------------+
|         1         |     1        |          500          |
|         2         |     1        |          700          |
|         3         |     1        |          600          |
|         4         |     2        |          200          |
|         5         |     2        |          150          |
|         6         |     3        |          900          |
+-------------------+--------------+-----------------------+

table invoice
+--------------+-------------------+------------------+
|  invoice_id  | client_project_id |  invoice_number  |
+--------------+-------------------+------------------+
|       1      |          23       |   I/01/2020/001  |
|       2      |          17       |   I/01/2020/002  |
|       3      |          54       |   I/01/2020/003  |
+--------------+-------------------+------------------+

table invoice_item
+-------------------+--------------+-----------------------+
|  invoice_item_id  |  invoice_id  |  invoice_item_amount  |
+-------------------+--------------+-----------------------+
|         1         |     1        |          500          |
|         2         |     1        |          700          |
|         3         |     1        |          600          |
|         4         |     2        |          200          |
|         5         |     2        |          150          |
|         6         |     3        |          900          |
+-------------------+--------------+-----------------------+

我需要得到的结果是：

每个客户\项目\ id的报价\项目\金额和发票\项目\金额之和 查询SUMinvoice

SELECT 
    SUM(quotation_item.quotation_item_amount) as quot_amt, 
    SUM(invoice_item.invoice_item_amount) as inv_amt,
    data_client_project.client_project_id,
    data_client.client_name

FROM data_client_project a
LEFT JOIN quotation b ON a.client_project_id = b.client_project_id
LEFT JOIN data_client d ON a.client_id = d.client_id
LEFT JOIN invoice i ON a.client_project_id = i.client_project_id
JOIN (
        SELECT quotation_id, 
            SUM(c.quotation_item_amount) as quot_amt
        FROM quotation_item c 
        GROUP BY c.quotation_id
      ) quotitem
        ON b.quotation_id = quotitem.quotation_id
        JOIN (
            SELECT invoice_id, 
                SUM(e.invoice_item_price) as inv_amt
            FROM invoice_item e
            GROUP BY e.invoice_id
        ) invitem
        ON i.invoice_id = invitem.invoice_id

但是，这会导致报价单项目金额和发票项目金额的多个重复行

已尝试使用UNION/UNION ALL和其他几个不起作用的查询。

---

感谢您的所有建议。

我可能遗漏了一些内容，但您的表说明中未包含data\u client或data\u client\u项目的示例鉴于您的示例，我希望您的行扩展来自前3个联接

确保以下内容首先为您提供了所需的数据列表，然后尝试加入计算：

SELECT *
    FROM data_client_project a
    LEFT JOIN quotation b ON a.client_project_id = b.client_project_id
    LEFT JOIN data_client d ON a.client_id = d.client_id
    LEFT JOIN invoice i ON a.client_project_id = i.client_project_id;
#you may want to append the above with a limit 100 for testing.

---

如果主查询中有重复的行，则只为obatin a添加不同的行 and和D根据quotitem.QUOTE“U amt

    SELECT distinct a.*, b.*, d.*, i.*  
    FROM data_client_project a
    LEFT JOIN quotation b ON a.client_project_id = b.client_project_id
    LEFT JOIN data_client d ON a.client_id = d.client_id
    LEFT JOIN invoice i ON a.client_project_id = i.client_project_id
    JOIN (
            SELECT quotation_id, 
                SUM(c.quotation_item_amount * c.quotation_item_qty) as quot_amt
            FROM quotation_item c 
            GROUP BY c.quotation_id
          ) quotitem  ON b.quotation_id = quotitem.quotation_id
    JOIN (
            SELECT invoice_id, 
                SUM(e.invoice_item_price) as inv_amt
            FROM invoice_item e
            GROUP BY e.invoice_id
            ) invitem  ON i.invoice_id = invitem.invoice_id
    WHERE quotitem.quot_amt < invitem.inv_amt

---

看起来您正试图同时沿两个不同的维度进行聚合。解决方案是沿每个维度进行预聚合：

SELECT *
FROM data_client_project cp LEFT JOIN
     (SELECT q.client_project_id,
             SUM(qi.quotation_item_amount * qi.quotation_item_qty) as quot_amt
      FROM quotation q JOIN
           quotation_item qi
           ON qi.quotation_id = q.quotation_id
      GROUP BY q.client_project_id
     ) q
     USING (client_project_id) LEFT JOIN
     (SELECT i.client_project_id,
             SUM(invoice_item_price) as inv_amt
      FROM invoice i JOIN
           invoice_item ii
           ON i.invoice_id = ii.invoice_id
      GROUP BY i.client_project_id
     ) i
     USING (client_project_id);

关于你的风格的两个注释

首先，您使用任意字母作为表别名。这使得查询很难理解，如果添加新表、删除表或重新排列名称，则查询会变得非常笨拙。在表格中使用缩写。更容易理解

---

第二，对于这样的查询，我并不推荐SELECT*。但是，如果要包含用于创建表并用数据填充的脚本，可以通过使用替换ON来避免重复的列。

，或者，如果你可以在sqlfiddle.com或db-fiddle.com这样的网站上这样做，然后在你的问题中发布链接，那么其他人会更容易帮助你获得问题的答案。此外，如果您可以提供当前查询所提供的结果集示例，以及该结果集的外观示例，请确保清楚指出两者之间的差异，这将非常有帮助。请注意：以上不是完整的答案。但是试图帮助提供信息。正如Gharbad所指出的，在db-FIDLE.com中添加的示例数据会带来奇迹。感谢您的建议，但是这个返回错误：“on子句”中的未知列“qi.quote_id”，我猜这是因为第二部分？对于SELECT*就是一个示例，在实时情况下，我会特别选择我编辑的问题中的每一列，特别选择SumQuotence“U item.Quotence“U item”amount作为Quote“amt”，SUMinvoice“U item.invoice”item“amount作为inv”作为inv“amt”，data“client”project.client“project”id，data“client”client.client_name@Charas . . . 我修正了条款，谢谢你！它确实按预期工作，但是当我在末尾添加I.inv_amt>q.quot_amt时，它没有返回正确的数据，或者我是否将其放在了错误的位置？