单击PHP页面上的提交按钮时执行多个sql查询
我有一个PHP页面，单击submit按钮可以处理一些MySQL查询 在MySQL PHPMyAdmin中，查询100%工作，两个查询都执行。但是，在我的PHP代码中，查询不会执行 任何帮助将不胜感激，我打赌这是一个体面的PHP程序员简单的一个 提前谢谢你，瑞安 我的代码是：单击PHP页面上的提交按钮时执行多个sql查询,php,mysql,submit,onsubmit,Php,Mysql,Submit,Onsubmit,我有一个PHP页面，单击submit按钮可以处理一些MySQL查询 在MySQL PHPMyAdmin中，查询100%工作，两个查询都执行。但是，在我的PHP代码中，查询不会执行 任何帮助将不胜感激，我打赌这是一个体面的PHP程序员简单的一个 提前谢谢你，瑞安 我的代码是： <?php mysql_connect("localhost", "hulamin_hulamin", "Hulamin2011")or die("cannot connect"); mysql
<?php
mysql_connect("localhost", "hulamin_hulamin", "Hulamin2011")or die("cannot connect");
mysql_select_db("hulamin_loc")or die("cannot select DB");
$sql="SELECT `dispatcharea`,`customer`,`casenumber`,`weight` from loaddetails where loadid = 0 order by dispatcharea";
$result=mysql_query($sql);
$count=mysql_num_rows($result);
?>
<html>
<head>
<title>
Plan Local PMB Delivery - Step 2
</title>
</head>
<html>
<table border=0>
<tr>
<td>
<form name="form1" method="post">
<table border=1>
<tr>
<td width=150>Dispatch Area</td>
<td width=300>Customer</td>
<td width=150>Case Number</td>
<td width=100>Weight</td>
</tr>
<?php
while($rows=mysql_fetch_array($result)){
?>
<tr>
<td><?php echo $rows['dispatcharea']; ?></td>
<td><?php echo $rows['customer']; ?></td>
<td><?php echo $rows['casenumber']; ?></td>
<td><?php echo $rows['weight']; ?></td>
</tr>
<?php
}
?>
</table>
<input name="Next" type="submit" id="Next" value="Next">
<?php
if($_REQUEST['Next']=='Next') {
{
$sql="update loaddetails set loadid= (select max(loadid)+1 from loadcounterid) where loadid=0; update loadcounterid set loadid= (select max(loadid) from loaddetails) where loadid>0;";
$final=mysql_query($sql);
if($final)
{
echo "<meta http-equiv=\"refresh\" content=\"0;URL=planlocalpmbstep3.php\">";
}
}
}
?>
</table>
</form>
</td>
</tr>
</table>
Ryan我认为这可能是你的问题
while($rows=mysql_fetch_array($result)){
while($rows=mysql_fetch_assoc($result)){
echo $rows['dispatcharea'];
// First update query
$sql1="update loaddetails set loadid= (select max(loadid)+1 from loadcounterid) where loadid=0";
// Second update query
$sql2="update loadcounterid set loadid= (select max(loadid) from loaddetails) where loadid>0";
// Run both queries independently
$final_query1 = mysql_query($sql1);
$final_query2 = mysql_query($sql2);
// Check for query success
if ($final_query1 && $final_query2)
{
// Success running the queries
}
else
{
// Unsuccessful running the queries
}
我认为这可能是你的问题
while($rows=mysql_fetch_array($result)){
while($rows=mysql_fetch_assoc($result)){
echo $rows['dispatcharea'];
// First update query
$sql1="update loaddetails set loadid= (select max(loadid)+1 from loadcounterid) where loadid=0";
// Second update query
$sql2="update loadcounterid set loadid= (select max(loadid) from loaddetails) where loadid>0";
// Run both queries independently
$final_query1 = mysql_query($sql1);
$final_query2 = mysql_query($sql2);
// Check for query success
if ($final_query1 && $final_query2)
{
// Success running the queries
}
else
{
// Unsuccessful running the queries
}
根据PHP文档，它不支持多个查询。PHPMyAdmin可能在执行查询之前分离查询。尝试将查询分为两部分。另外，PHP文档说不应该以分号结束mysql_查询，但这似乎没有什么坏处。根据PHP文档，不支持多个查询。PHPMyAdmin可能在执行查询之前分离查询。尝试将查询分为两部分。另外，PHP文档说不应该以分号结束mysql_查询，但这似乎没有什么坏处。如果您想同时执行多个查询，可以改用mysqli函数 有一个mysqli函数mysqli_multi_query，可用于一次执行多个查询 请参阅： 下面是以面向对象的方式使用mysqli_multi_查询对代码的粗略重写：
<?php
$link = mysqli_connect('localhost', 'hulamin_hulamin', 'Hulamin2011', 'hulamin_loc');
$sql = "SELECT `dispatcharea`,`customer`,`casenumber`,`weight` from loaddetails where loadid = 0 order by dispatcharea";
$result = $link->query($sql);
$count = $result->num_rows($result);
?>
<html>
<head>
<title>
Plan Local PMB Delivery - Step 2
</title>
</head>
<html>
<table border=0>
<tr>
<td>
<form name="form1" method="post">
<table border=1>
<tr>
<td width=150>Dispatch Area</td>
<td width=300>Customer</td>
<td width=150>Case Number</td>
<td width=100>Weight</td>
</tr>
<?php
while($rows = $link->fetch_array($result)){
?>
<tr>
<td><?php echo $rows['dispatcharea']; ?></td>
<td><?php echo $rows['customer']; ?></td>
<td><?php echo $rows['casenumber']; ?></td>
<td><?php echo $rows['weight']; ?></td>
</tr>
<?php
}
?>
</table>
<input name="Next" type="submit" id="Next" value="Next">
<?php
if($_REQUEST['Next']=='Next'){
{
$multi_sql = "update loaddetails set loadid= (select max(loadid)+1 from loadcounterid) where loadid=0;";
$multi_sql .= "update loadcounterid set loadid= (select max(loadid) from loaddetails) where loadid>0";
$final = $link->multi_query($multi_sql);
if($final)
{
echo "<meta http-equiv=\"refresh\" content=\"0;URL=planlocalpmbstep3.php\">";
} }
}
?>
</table>
</form>
</td>
</tr>
</table>
如果您想同时执行多个查询，可以改用mysqli函数 有一个mysqli函数mysqli_multi_query，可用于一次执行多个查询 请参阅： 下面是以面向对象的方式使用mysqli_multi_查询对代码的粗略重写：
<?php
$link = mysqli_connect('localhost', 'hulamin_hulamin', 'Hulamin2011', 'hulamin_loc');
$sql = "SELECT `dispatcharea`,`customer`,`casenumber`,`weight` from loaddetails where loadid = 0 order by dispatcharea";
$result = $link->query($sql);
$count = $result->num_rows($result);
?>
<html>
<head>
<title>
Plan Local PMB Delivery - Step 2
</title>
</head>
<html>
<table border=0>
<tr>
<td>
<form name="form1" method="post">
<table border=1>
<tr>
<td width=150>Dispatch Area</td>
<td width=300>Customer</td>
<td width=150>Case Number</td>
<td width=100>Weight</td>
</tr>
<?php
while($rows = $link->fetch_array($result)){
?>
<tr>
<td><?php echo $rows['dispatcharea']; ?></td>
<td><?php echo $rows['customer']; ?></td>
<td><?php echo $rows['casenumber']; ?></td>
<td><?php echo $rows['weight']; ?></td>
</tr>
<?php
}
?>
</table>
<input name="Next" type="submit" id="Next" value="Next">
<?php
if($_REQUEST['Next']=='Next'){
{
$multi_sql = "update loaddetails set loadid= (select max(loadid)+1 from loadcounterid) where loadid=0;";
$multi_sql .= "update loadcounterid set loadid= (select max(loadid) from loaddetails) where loadid>0";
$final = $link->multi_query($multi_sql);
if($final)
{
echo "<meta http-equiv=\"refresh\" content=\"0;URL=planlocalpmbstep3.php\">";
} }
}
?>
</table>
</form>
</td>
</tr>
</table>
我想我会发布我的完整代码，现在正在工作。感谢所有回答我问题的人，我非常感谢。成为这个反应如此迅速的社区的一员真是太棒了 我的代码是：
<?php
mysql_connect("localhost", "username", "password")or die("cannot connect");
mysql_select_db("dbname")or die("cannot select DB");
$sql="SELECT `dispatcharea`,`customer`,`casenumber`,`weight` from loaddetails where loadid = 0 order by dispatcharea";
$result=mysql_query($sql);
$count=mysql_num_rows($result);
?>
<html>
<head>
<title>
Plan Local PMB Delivery - Step 2
</title>
</head>
<html>
<table>
<tr>
<td>
<center>
Load Number
</td>
<td>
<center>
Number of Cases
</td>
<td>
<center>
Load Weight
</td>
<td>
<center>
Other Detail
</td>
</tr>
<tr>
<td width=150>
<center>
<?php
$loadid = mysql_query('SELECT max(loadid)+1 FROM loaddetails');
if (!$loadid) {
die('Could not query:' . mysql_error());
}
echo mysql_result($loadid, 0);
?>
</td>
<td width=150>
<center>
<?php
$nocases = mysql_query('SELECT count(*) FROM loaddetails where loadid = 0');
if (!$nocases) {
die('Could not query:' . mysql_error());
}
echo mysql_result($nocases, 0);
?>
</td>
<td width=150>
<center>
<?php
$weight = mysql_query('SELECT SUM(WEIGHT) FROM loaddetails where loadid = 0');
if (!$loadid) {
die('Could not query:' . mysql_error());
}
echo mysql_result($weight, 0);
?>
</td>
<td width=150>
<center>
</td>
</tr>
</table>
<hr>
<table border=0>
<tr>
<td>
<form name="form1" method="post">
<table border=1>
<tr>
<td width=150>Dispatch Area</td>
<td width=300>Customer</td>
<td width=150>Case Number</td>
<td width=100>Weight</td>
</tr>
<?php
while($rows=mysql_fetch_array($result)){
?>
<tr>
<td><?php echo $rows['dispatcharea']; ?></td>
<td><?php echo $rows['customer']; ?></td>
<td><?php echo $rows['casenumber']; ?></td>
<td><?php echo $rows['weight']; ?></td>
</tr>
<?php
}
?>
</table>
<input name="Next" type="submit" id="Next" value="Next">
<?php
// First update query
$sql1="update loaddetails set loadid= (select max(loadid)+1 from loadcounterid) where loadid=0";
// Second update query
$sql2="update loadcounterid set loadid= (select max(loadid) from loaddetails) where loadid>0";
if($_REQUEST['Next']=='Next'){
// Run both queries independently
$final_query1 = mysql_query($sql1);
$final_query2 = mysql_query($sql2);
if ($final_query1 && $final_query2)
{
// Success running the queries
echo "<meta http-equiv=\"refresh\" content=\"0;URL=planlocalpmbstep3.php\">";
}
else
{
// Unsuccessful running the queries
}
}
?>
</table>
</form>
</td>
</tr>
</table>
我想我会发布我的完整代码，现在正在工作。感谢所有回答我问题的人，我非常感谢。成为这个反应如此迅速的社区的一员真是太棒了 我的代码是：
<?php
mysql_connect("localhost", "username", "password")or die("cannot connect");
mysql_select_db("dbname")or die("cannot select DB");
$sql="SELECT `dispatcharea`,`customer`,`casenumber`,`weight` from loaddetails where loadid = 0 order by dispatcharea";
$result=mysql_query($sql);
$count=mysql_num_rows($result);
?>
<html>
<head>
<title>
Plan Local PMB Delivery - Step 2
</title>
</head>
<html>
<table>
<tr>
<td>
<center>
Load Number
</td>
<td>
<center>
Number of Cases
</td>
<td>
<center>
Load Weight
</td>
<td>
<center>
Other Detail
</td>
</tr>
<tr>
<td width=150>
<center>
<?php
$loadid = mysql_query('SELECT max(loadid)+1 FROM loaddetails');
if (!$loadid) {
die('Could not query:' . mysql_error());
}
echo mysql_result($loadid, 0);
?>
</td>
<td width=150>
<center>
<?php
$nocases = mysql_query('SELECT count(*) FROM loaddetails where loadid = 0');
if (!$nocases) {
die('Could not query:' . mysql_error());
}
echo mysql_result($nocases, 0);
?>
</td>
<td width=150>
<center>
<?php
$weight = mysql_query('SELECT SUM(WEIGHT) FROM loaddetails where loadid = 0');
if (!$loadid) {
die('Could not query:' . mysql_error());
}
echo mysql_result($weight, 0);
?>
</td>
<td width=150>
<center>
</td>
</tr>
</table>
<hr>
<table border=0>
<tr>
<td>
<form name="form1" method="post">
<table border=1>
<tr>
<td width=150>Dispatch Area</td>
<td width=300>Customer</td>
<td width=150>Case Number</td>
<td width=100>Weight</td>
</tr>
<?php
while($rows=mysql_fetch_array($result)){
?>
<tr>
<td><?php echo $rows['dispatcharea']; ?></td>
<td><?php echo $rows['customer']; ?></td>
<td><?php echo $rows['casenumber']; ?></td>
<td><?php echo $rows['weight']; ?></td>
</tr>
<?php
}
?>
</table>
<input name="Next" type="submit" id="Next" value="Next">
<?php
// First update query
$sql1="update loaddetails set loadid= (select max(loadid)+1 from loadcounterid) where loadid=0";
// Second update query
$sql2="update loadcounterid set loadid= (select max(loadid) from loaddetails) where loadid>0";
if($_REQUEST['Next']=='Next'){
// Run both queries independently
$final_query1 = mysql_query($sql1);
$final_query2 = mysql_query($sql2);
if ($final_query1 && $final_query2)
{
// Success running the queries
echo "<meta http-equiv=\"refresh\" content=\"0;URL=planlocalpmbstep3.php\">";
}
else
{
// Unsuccessful running the queries
}
}
?>
</table>
</form>
</td>
</tr>
</table>
为什么不在对mysql_query的两个单独调用中运行这两个查询呢？Hu@mishu，你能告诉我如何在现有代码上这样做吗？我如何在一次点击按钮时有两个动作？谢谢你为什么不在mysql_query的两个单独调用中运行这两个查询？Hu@mishu，你能告诉我如何在现有的代码上这样做吗？我如何在一次点击按钮时有两个动作？默认情况下，Thanksmysql_fetch_数组同时返回数值数组和关联数组。这是一个正确的观点，但这只是因为默认的结果类型是“MYSQL\u-BOTH”。它并不认为内容没有用处，但仍然值得注意的是，特定的函数是可用的。可能是，但肯定不是在answerHi中，输出从数组正确返回。它是不更新的mysql查询。有什么建议吗？请参考编辑和代码添加。即使使用单个mysql\u查询函数以分号分隔，也不能运行两个查询。默认情况下，mysql\u fetch\u数组同时返回数字数组和关联数组。这是一个正确的观点，但这只是因为默认的结果类型是“MYSQL\u-BOTH”。它并不认为内容没有用处，但仍然值得注意的是，特定的函数是可用的。可能是，但肯定不是在answerHi中，输出从数组正确返回。它是不更新的mysql查询。有什么建议吗？请参考编辑和代码添加。即使使用一个mysql_查询函数以分号分隔，也不能运行两个查询。您是对的@arxanas，PHPMyAdmin将其分解为两个查询。我怎样才能把它分成两部分？谢谢你的回答@arxanas，PHPMyAdmin将其分解为两个查询。我怎样才能把它分成两部分？很高兴看到这篇文章被否决。mysqli_multi_query非常适合这个实现——特别是在一个字符串中执行多个更新mysql查询。嗨@Luke，我读了一些你提供的链接，我如何在单击提交按钮时执行所有mysql语句？Thanks@RyanSmith请看我贴在上面的代码。不管怎样，我已经从mysql的角度重写了整段代码。非常感谢，你们太棒了！现在工作得很好！干杯，伙计们！很高兴听到！D
您是将查询拆分，还是最终使用mysqli？看到这篇文章被否决令人失望。mysqli_multi_query非常适合这个实现——特别是在一个字符串中执行多个更新mysql查询。嗨@Luke，我读了一些你提供的链接，我如何在单击提交按钮时执行所有mysql语句？Thanks@RyanSmith请看我贴在上面的代码。不管怎样，我已经从mysql的角度重写了整段代码。非常感谢，你们太棒了！现在工作得很好！干杯，伙计们！很高兴听到！您是将查询拆分，还是最终使用了mysqli？