PHP jsonSerialize接口和jsonSerialize与嵌套对象

我有一个

ResponseGrid

对象，我想用Json对它进行编码。此对象内部有一个

$row

变量，该变量将包含一个

文档

对象数组

我在

ResponseGrid

和

Document

中实现了

JsonSerializable

接口和

jsonSerialize（）

方法

我得到的是：

ResponseGrid.php:

require_once ROOT_DIR . "/business/models/Document.php";

class ResponseGrid implements JsonSerializable {

    private $sEcho;
    private $iTotalRecords;
    private $iTotalDisplayRecords;
    private $rows; // This will contain an Array of Documents

    public function jsonSerialize() {
        return [
            'sEcho' => $this->sEcho,
            'iTotalRecords' => $this->iTotalRecords,
            'iTotalDisplayRecords' => $this->iTotalDisplayRecords,
            'rows' => json_encode($this->rows), //This will cause troubles
        ];
    }
}

class Document implements JsonSerializable {

    private $id;
    private $name;
    private $description;
    private $contentId;

    public function jsonSerialize() {
        return [
            'id' => $this->id,
            'name' => $this->name,
            'description' => $this->description,
            'contentId' => $this->contentId, 
        ];
    }
}

Document.php:

require_once ROOT_DIR . "/business/models/Document.php";

class ResponseGrid implements JsonSerializable {

    private $sEcho;
    private $iTotalRecords;
    private $iTotalDisplayRecords;
    private $rows; // This will contain an Array of Documents

    public function jsonSerialize() {
        return [
            'sEcho' => $this->sEcho,
            'iTotalRecords' => $this->iTotalRecords,
            'iTotalDisplayRecords' => $this->iTotalDisplayRecords,
            'rows' => json_encode($this->rows), //This will cause troubles
        ];
    }
}

class Document implements JsonSerializable {

    private $id;
    private $name;
    private $description;
    private $contentId;

    public function jsonSerialize() {
        return [
            'id' => $this->id,
            'name' => $this->name,
            'description' => $this->description,
            'contentId' => $this->contentId, 
        ];
    }
}

如果我对

$row

数组中填充了两个文档的

ResponseGrid

对象进行回显，我会得到以下结果

echo json_encode（$responseGrid）

为什么呢？我做错了吗？所有这些反斜杠是什么？
在对象再次进行json编码之前，您正在对其进行json编码。您只需将行添加到ResponseGrid对象中，无需对其进行编码。您看到的是表示文档的转义字符串object@PatrickEvans你说得对：我在
'rows'=>$this->rows
中更改了
'rows'=>json\u编码（$this->rows）
，现在一切都正常了。非常感谢。如果你把它写在回信里，我会接受的：）