如何从json_编码php中删除数组索引

我试图删除json 2d数组中显示的数字。我首先有一个2d数组，它是动态的，并从该数组中删除元素。然后将该数组转换为json 2d数组。问题是我一开始就不想要数字

如下所示

[ 

"1": {"StateName":"Alaska","StateAbbr":"AK"}, 
"2": {"StateName":"Alabama","StateAbbr":"AL"}, 
"3": {"StateName":"Arkansas","StateAbbr":"AR"}, 
"4": {"StateName":"Arizona","StateAbbr":"AZ"}, 
"5": {"StateName":"California","StateAbbr":"CA"}, 
"6": {"StateName":"Colorado","StateAbbr":"CO"}, 
"7": {"StateName":"Connecticut","StateAbbr":"CT"} 

]  

我希望它是这样的

[ 

{"StateName":"Alaska","StateAbbr":"AK"}, 
{"StateName":"Alabama","StateAbbr":"AL"}, 
{"StateName":"Arkansas","StateAbbr":"AR"}, 
{"StateName":"Arizona","StateAbbr":"AZ"}, 
{"StateName":"California","StateAbbr":"CA"}, 
{"StateName":"Colorado","StateAbbr":"CO"}, 
{"StateName":"Connecticut","StateAbbr":"CT"} 

]

没有数字。我该怎么做

我试过mysql_fetch_assoc，但没用

$arr = array();
while($row = mysql_fetch_assoc($result)) {
  $arr[] = $row; 
}
echo json_encode($arr);

---

我了解了如何在转换为json后从2d数组中删除键。为此创建函数

function remove_json_keys($array) {
  foreach ($array as $k => $v) {
    if (is_array($v)) {
        $array[$k] = $this->remove_json_keys($v);
    } //if
  } //foreach
  return $this->sort_numeric_keys($array);
}

function sort_numeric_keys($array) {
    $i=0;
    foreach($array as $k => $v) {
        if(is_int($k)) {
            $rtn[$i] = $v;
            $i++;
        } else {
            $rtn[$k] = $v;
        } //if
    } //foreach
    return $rtn;
}

---

不，这将无法在二维阵列中使用动态关键帧。谢谢你的回复。