Php 使用GoogleImagesAPI和CURL检索图像时总是得到相同的链接
我正在尝试使用Google的API和PHP获取大量不同的图像。代码对单个图像很有效,但是当我尝试在for循环中使用相同的代码获取不同主题的图像时,我总是只得到第一个结果:Php 使用GoogleImagesAPI和CURL检索图像时总是得到相同的链接,php,curl,Php,Curl,我正在尝试使用Google的API和PHP获取大量不同的图像。代码对单个图像很有效,但是当我尝试在for循环中使用相同的代码获取不同主题的图像时,我总是只得到第一个结果: $images = array("ironman poster", "superman returns poster", "the croods poster", "batman forever poster"); foreach ($images as $i) { $image = rawurlencode($i)
$images = array("ironman poster", "superman returns poster", "the croods poster", "batman forever poster");
foreach ($images as $i) {
$image = rawurlencode($i);
$query = "https://ajax.googleapis.com/ajax/services/search/images?v=1.0&q=".$image."&imgsz=large&as_filetype=jpg";
$json = get_url_contents($query);
$data = json_decode($json);
foreach ($data->responseData->results as $result) {
$results[] = array("url" => $result->url, "alt" => $result->title);
}
echo $results[0]['url'];
echo "<br />";
echo $query;
echo "<br />";
}
function get_url_contents($url) {
$crl = curl_init();
curl_setopt($crl, CURLOPT_USERAGENT, 'Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; .NET CLR 1.1.4322)');
curl_setopt($crl, CURLOPT_URL, $url);
curl_setopt($crl, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($crl, CURLOPT_CONNECTTIMEOUT, 5);
$ret = curl_exec($crl);
curl_close($crl);
return $ret;
}
$images=array(“铁人海报”、“超人归来海报”、“克罗兹海报”、“永远的蝙蝠侠海报”);
foreach($i形式的图像){
$image=rawurlencode($i);
$query=”https://ajax.googleapis.com/ajax/services/search/images?v=1.0&q=“$image.”&imgsz=large&as_filetype=jpg”;
$json=get\u url\u contents($query);
$data=json_decode($json);
foreach($data->responseData->results as$result){
$results[]=array(“url”=>$result->url,“alt”=>$result->title);
}
echo$results[0]['url'];
回声“
”;
echo$query;
回声“
”;
}
函数获取url内容($url){
$crl=curl_init();
curl_setopt($crl,CURLOPT_USERAGENT,'Mozilla/4.0(兼容;MSIE 6.0;Windows NT 5.1;.NET CLR 1.1.4322)');
curl_setopt($crl,CURLOPT_URL,$URL);
curl_setopt($crl,CURLOPT_RETURNTRANSFER,1);
curl_setopt($crl,CURLOPT_CONNECTTIMEOUT,5);
$ret=curl\u exec($crl);
卷曲关闭($crl);
返回$ret;
}
在循环迭代之前,需要定义$results
数组。我不确定为什么它不起作用,也许其他人可以解释一下
工作解决方案:
$images=array(“铁人海报”、“超人归来海报”、“克罗伊兹海报”、“永远的蝙蝠侠海报”)
foreach($i图像){
$image=rawurlencode($i);
$query=”https://ajax.googleapis.com/ajax/services/search/images?v=1.0&q=“$image.”&imgsz=large&as_filetype=jpg”;
$json=get\u url\u contents($query);
$data=json_decode($json);
$results=array();//在这里定义数组!
foreach($data->responseData->results as$result){
$results[]=array(“url”=>$result->url,“alt”=>$result->title);
}
echo$results[0]['url'];
回声“
”;
echo$query;
回声“
”;
}
foreach ($images as $i) {
$image = rawurlencode($i);
$query = "https://ajax.googleapis.com/ajax/services/search/images?v=1.0&q=".$image."&imgsz=large&as_filetype=jpg";
$json = get_url_contents($query);
$data = json_decode($json);
$results = array(); //define array here!
foreach ($data->responseData->results as $result) {
$results[] = array("url" => $result->url, "alt" => $result->title);
}
echo $results[0]['url'];
echo "<br />";
echo $query;
echo "<br />";
}