PHP&;MongoDB显示按日期分组的结果
我有一个mongodb集合,其中包含以下文档:PHP&;MongoDB显示按日期分组的结果,php,mongodb,aggregation-framework,Php,Mongodb,Aggregation Framework,我有一个mongodb集合,其中包含以下文档: { "_id" : ObjectId("547af6aea3f0eba7148b4567"), "check_id" : "f5d654e7-257d-4a93-ae50-2d59dfeeb451", "chunks" : NumberLong(200), "num_hosts" : NumberLong(1000), "num_rbls" : NumberLong(163), "owner" : NumberLong(79
{
"_id" : ObjectId("547af6aea3f0eba7148b4567"),
"check_id" : "f5d654e7-257d-4a93-ae50-2d59dfeeb451",
"chunks" : NumberLong(200),
"num_hosts" : NumberLong(1000),
"num_rbls" : NumberLong(163),
"owner" : NumberLong(7901),
"created" : ISODate("2014-11-30T10:51:26.924Z"),
"started" : ISODate("2014-11-30T10:51:31.558Z"),
"finished" : ISODate("2014-11-30T10:57:08.512Z")
}
{
"_id" : ObjectId("54db19a858a5d395a18b4567"),
"check_id" : "9660e510-1349-43f3-9d5e-8bf4b06179be",
"chunks" : NumberLong(2),
"num_hosts" : NumberLong(10),
"num_rbls" : NumberLong(166),
"owner" : NumberLong(7901),
"created" : ISODate("2015-02-11T08:58:17.118Z"),
"started" : ISODate("2015-02-11T08:58:18.78Z"),
"finished" : ISODate("2015-02-11T08:58:47.486Z")
}
{
"_id" : ObjectId("54db267758a5d30eab8b4567"),
"check_id" : "9660e510-1349-43f3-9d5e-8bf4b06179be",
"chunks" : NumberLong(2),
"num_hosts" : NumberLong(10),
"num_rbls" : NumberLong(166),
"owner" : NumberLong(7901),
"created" : ISODate("2015-02-11T09:52:55.388Z"),
"started" : ISODate("2015-02-11T09:52:56.109Z"),
"finished" : ISODate("2015-02-11T09:53:22.095Z")
}
我需要的是得到结果并生成类似于以下内容的数组:
Array
(
[2015-02-11] => array
(
//array with results from 2015-02-11
)
[2014-11-30] => array
(
//array with results from 2014-11-30
)
)
我知道可以只执行简单的collection->find,然后循环遍历结果,并使用php逻辑来实现我的目标,但是可以使用mongo实现吗?也许使用聚合框架
编辑:我想按“创建”日期对结果进行分组
任何帮助都将不胜感激。Monogo聚合组用于此,因此下面的查询可能会解决您的问题
db.collectionName.aggregate({
"$group": {
"_id": "$created",
"data": {
"$push": {
"check_id": "$check_id",
"chunks": "$chunks",
"num_hosts": "$num_hosts",
"num_rbls": "$num_rbls",
"owner": "$owner",
"started": "$started",
"finished": "$finished"
}
}
}
}).pretty()
或
在Mongo2.8中还提供了将ISO日期转换为字符串格式的工具,因此下面的查询也可以工作
db.collectionName.aggregate([
{
"$project": {
"yearMonthDay": {
"$dateToString": {
"format": "%Y-%m-%d",
"date": "$created"
}
},
"check_id": "$check_id",
"chunks": "$chunks",
"num_hosts": "$num_hosts",
"num_rbls": "$num_rbls",
"owner": "$owner",
"started": "$started",
"finished": "$finished"
}
},
{
"$group": {
"_id": "$yearMonthDay",
"data": {
"$push": "$$ROOT"
}
}
}
]).pretty()
我已经使用聚合框架解决了这个问题。这是答案,以防有人需要
$op = array(
array(
'$project' => array(
'data' => array(
'check_id' => '$check_id',
'chunks' => '$chunks',
'num_hosts' => '$num_hosts',
'num_rbls' => '$num_rbls',
'owner' => '$owner',
'started' => '$started',
'finished' => '$finished',
),
'year' => array('$year' => '$created' ),
'month' => array('$month' => '$created' ),
'day' => array('$dayOfMonth' => '$created'),
)
),
array(
'$group' => array(
'_id' => array('year' => '$year', 'month' => '$month', 'day' => '$day'),
'reports_data' => array('$push' => '$data'),
)
),
);
$c = $collection->aggregate($op);
您希望按创建、开始或完成的日期分组?@yogesh谢谢!我想按创建日期对其进行分组。@Мццццааацццааааааа。我已将其更改为我的收藏名称。确定是否显示任何错误?但是,我不知道上面的相同文档向我显示了结果@Мцццааааа嗨,我找到了另一种方法,我认为这也会对您有所帮助。
$op = array(
array(
'$project' => array(
'data' => array(
'check_id' => '$check_id',
'chunks' => '$chunks',
'num_hosts' => '$num_hosts',
'num_rbls' => '$num_rbls',
'owner' => '$owner',
'started' => '$started',
'finished' => '$finished',
),
'year' => array('$year' => '$created' ),
'month' => array('$month' => '$created' ),
'day' => array('$dayOfMonth' => '$created'),
)
),
array(
'$group' => array(
'_id' => array('year' => '$year', 'month' => '$month', 'day' => '$day'),
'reports_data' => array('$push' => '$data'),
)
),
);
$c = $collection->aggregate($op);