Php 从带有preg_匹配的页面代码中查找链接

我想使用preg_match更改此选项：

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我怎么做？我正在尝试使用preg\u match，但是这个链接太复杂了…

使用preg\u match确实太复杂了。正如在这个网站上多次提到的：regex+HTML不能很好地混合。Regex不适合处理标记。但是，DOM解析器是：

$dom = new DOMDocument;//create parser
$dom->loadHTML($htmlString);
$xpath = new DOMXPath($dom);//create XPath instance for dom, so we can query using xpath
$elemsWithHref = $xpath->query('//*[@href]');//get any node that has an href attribtue
$hrefs = array();//all href values
foreach ($elemsWithHref as $node)
{
    $hrefs[] = $node->getAttributeNode('href')->value;//assign values
}

在此之后，只需处理$hrefs中的值，这将是一个字符串数组，每个字符串都是href属性的值

使用DOM解析器和XPath向您展示其功能的另一个示例：

要用href值替换节点，只需执行以下操作：

获取父节点 构造文本节点 调用DOMDocument:：replaceChild 通过调用save来写入文件，或者调用saveHTML或saveXML来获取作为字符串的DOM 例如：

$dom = new DOMDocument;//create parser
$dom->loadHTML($htmlString);
$xpath = new DOMXPath($dom);//create XPath instance for dom, so we can query using xpath
$elemsWithHref = $xpath->query('//*[@href]');//get any node that has an href attribtue
foreach ($elemsWithHref as $node)
{
    $parent = $node->parentNode;
    $replace = new DOMText($node->getAttributeNode('href')->value);//create text node
    $parent->replaceChild($replace, $node);//replaces $node with $replace textNode
}
$newString = $dom->saveHTML();

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@user3898993:如果您在处理标记时想到正则表达式，请记住：。。。这是一种传奇式的回答：

$dom = new DOMDocument;//create parser
$dom->loadHTML($htmlString);
$xpath = new DOMXPath($dom);//create XPath instance for dom, so we can query using xpath
$elemsWithHref = $xpath->query('//*[@href]');//get any node that has an href attribtue
foreach ($elemsWithHref as $node)
{
    $parent = $node->parentNode;
    $replace = new DOMText($node->getAttributeNode('href')->value);//create text node
    $parent->replaceChild($replace, $node);//replaces $node with $replace textNode
}
$newString = $dom->saveHTML();