Php 在输入字段旁边显示错误

我想在输入字段旁边显示错误。我尝试回显错误，但它只显示单词数组。如何在输入字段旁边显示错误？此外，我想让用户上传5张照片，只有第一张照片是必需的。我的意思是，用户可以上传5张照片，但所有的5张照片不是必需的，只有一张。可能吗？谢谢

    <?php
$out['error'][]=''; //this is what I added
function uploadFile ($file_field = null, $check_image = false, $random_name = false) {

//Config Section    
//Set file upload path
$path = 'productpic/'; //with trailing slash
//Set max file size in bytes
$max_size = 2097152;
//Set default file extension whitelist
$whitelist_ext = array('jpg','png','gif');
//Set default file type whitelist
$whitelist_type = array('image/jpeg', 'image/png','image/gif');

//The Validation
// Create an array to hold any output
$out = array('error'=>null);

if (!$file_field) {
$out['error'][] = "Please specify a valid form field name";           
}

if (!$path) {
$out['error'][] = "Please specify a valid upload path";               
}

if (count($out['error'])>0) {
return $out;
}

//Make sure that there is a file
if((!empty($_FILES[$file_field])) && ($_FILES[$file_field]['error'] == 0)) {

// Get filename
$file_info = pathinfo($_FILES[$file_field]['name']);
$name = $file_info['filename'];
$ext = $file_info['extension'];

//Check file has the right extension           
if (!in_array($ext, $whitelist_ext)) {
  $out['error'][] = "Invalid file Extension";
}

//Check that the file is of the right type
if (!in_array($_FILES[$file_field]["type"], $whitelist_type)) {
  $out['error'][] = "Invalid file Type";
}

//Check that the file is not too big
if ($_FILES[$file_field]["size"] > $max_size) {
  $out['error'][] = "We are sorry, the image must be less than 2MB";
}

//If $check image is set as true
if ($check_image) {
  if (!getimagesize($_FILES[$file_field]['tmp_name'])) {
    $out['error'][] = "The file you trying to upload is not an Image, we only accept images";
  }
}

//Create full filename including path
if ($random_name) {

  // Generate random filename
  $tmp = str_replace(array('.',' '), array('',''), microtime());

  if (!$tmp || $tmp == '') {
    $out['error'][] = "File must have a name";
  }     
  $newname = $tmp.'.'.$ext;                                
} else {
    $newname = $name.'.'.$ext;
}

//Check if file already exists on server
if (file_exists($path.$newname)) {
  $out['error'][] = "The image you trying to upload already exists, please upload only once";
}

if (count($out['error'])>0) {
  //The file has not correctly validated
  return $out;
} 

if (move_uploaded_file($_FILES[$file_field]['tmp_name'], $path.$newname)) {
  //Success

  $out['filepath'] = $path;
  $out['filename'] = $newname;
  return $out;
} else {
  $out['error'][] = "Server Error!";
}

} else {
$out['error'][] = "Please select a photo";
return $out;
}      
}
?>

<?php

if (isset($_POST['submit'])) {

$file = uploadFile('file', true, false);
if (is_array($file['error'])) {
$message = '';
foreach ($file['error'] as $msg) {
  $message .= '<p>'.$msg.'</p>';    
}
} else {
$message = "File uploaded successfully";
$sub=1;
}
echo $message;
}
?>
<form action="" method="post" enctype="multipart/form-data" name="form1" id="form1">
<?php
ini_set( "display_errors", 0);
if($sub==0)
{
?>
<input name="file" type="file" size="20" /><span><?php echo $out['error'] ;?></span> //It displays here just the word Array
<input name="submit" type="submit" value="Upload" />
<?php
}
?>
</form>

//这里只显示单词数组

因为

$out['error']

是一个数组，

echo

ing它将输出

array

，正如您所注意到的那样。要将其输出为字符串，首先需要转换它；这样做的一个选项是使用

内爆

。我建议使用

作为“粘合剂”，这样每个错误都会显示在不同的行上

所以

---

使用var_dump（）代替echo来检查涌入的数据..echo“”；var_dump（$out['error']）；而不是->echo$out['error']；这是因为

$out['error']

是每个代码的一个数组。它现在输出什么？就在输入字段旁边的“>”处，错误消息会像以前一样显示。那么我想你一定是复制错了。贴出你所拥有的东西。它不起作用。请告诉我问题的第二部分，我很乐意这样做。不管我是否能让它工作，错误信息的东西。如果你知道第二部分，请告诉我。谢谢你的帮助

<input name="file" type="file" size="20" /><span><?php echo implode('<br>', $out['error']) ;?></span> 
<input name="submit" type="submit" value="Upload" />

if ($first_check)
{
    $out['error'] = 'First error message';
}

elseif ($second_check)
{
    $out['error'] = 'Second error message';
}

else
{
    $out['success'] = 'Success message';
}