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php zend路由变量 Zend_路由代码问题_Php_Zend Framework_Routes - Fatal编程技术网
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php zend路由变量 Zend_路由代码问题

php zend-framework routes

php zend路由变量 Zend_路由代码问题,php,zend-framework,routes,Php,Zend Framework,Routes,此代码正在运行 resources.router.routes.babynameslist.route = "baby-names/baby-boy-names-list-from/:char resources.router.routes.babynameslist.defaults.module = "default" resources.router.routes.babynameslist.defaults.controller = "index" r

此代码正在运行

resources.router.routes.babynameslist.route               = "baby-names/baby-boy-names-list-from/:char
resources.router.routes.babynameslist.defaults.module     = "default"
resources.router.routes.babynameslist.defaults.controller = "index"
resources.router.routes.babynameslist.defaults.action     = "babynameslist"

但我想用这个

resources.router.routes.babynameslist.route               = "baby-names/baby-boy-names-list-from-:char/"
resources.router.routes.babynameslist.defaults.module     = "default"
resources.router.routes.babynameslist.defaults.controller = "index"
resources.router.routes.babynameslist.defaults.action     = "babynameslist"
它不工作（-：char/）

请帮助我如何制作“baby-boy-names-list-from-a”

我认为您应该将“a”传递给一个变量，并调整脚本的顺序。 我不确定，但我认为动态路线在Zend_路线中不起作用。

例如：

http://example.com/baby-names/baby-boy-names-list-from/a
您可以考虑使用
Zend\u控制器\u路由器\u路由\u正则表达式


定义如下：


resources.router.routes.babynameslist.type                = "Zend_Controller_Router_Route_Regex"
resources.router.routes.babynameslist.route               = "baby-names/baby-boy-names-list-from-(\w)/"
resources.router.routes.babynameslist.map.1               = "char"
resources.router.routes.babynameslist.defaults.module     = "default"
resources.router.routes.babynameslist.defaults.controller = "index"
resources.router.routes.babynameslist.defaults.action     = "babynameslist"