Php JSON fetch dosen'；不能在真实主机中正常工作，但可以在本地主机中工作

我的免费主机中有这个

json

：

正如您所看到的，如果在浏览器中运行此操作并获取两个参数，则获取工作正常。但是当把这个url放在我的android应用程序（截取）中时，不会获取任何内容。在上一篇文章中，当我在本地主机（xampp）中使用这个json时，一切都正常工作，但是当释放主机时，这个问题出现了

dbconfig.php

<?php
//Define your host here.
$servername = "xxx";
//Define your database username here.
$username = "xxx";
//Define your database password here.
$password = "*******";
//Define your database name here.
$dbname = "xxx";
?>

<?php 

include 'dbconfig.php';

$con = mysqli_connect($servername,$username,$password,$dbname);
 //creating a query
 $stmt = $con->prepare("SELECT POWER , ONE_THRUST_BEARING_METAL_TEMP

 FROM turbine_table ORDER BY id DESC LIMIT 1;");

 //executing the query 
 $stmt->execute();

 //binding results to the query 
 $stmt->bind_result($t1,$t2);

 $boiler = array(); 

 //traversing through all the result 
 while($stmt->fetch()){
 $temp = array();

$temp['t1'] = $t1;
$temp['t2'] = $t2;

 array_push($boiler, $temp);
 }

 //displaying the result in json format 
 echo json_encode($boiler);
 ?>

fetch_turbine2.php

<?php
//Define your host here.
$servername = "xxx";
//Define your database username here.
$username = "xxx";
//Define your database password here.
$password = "*******";
//Define your database name here.
$dbname = "xxx";
?>

<?php 

include 'dbconfig.php';

$con = mysqli_connect($servername,$username,$password,$dbname);
 //creating a query
 $stmt = $con->prepare("SELECT POWER , ONE_THRUST_BEARING_METAL_TEMP

 FROM turbine_table ORDER BY id DESC LIMIT 1;");

 //executing the query 
 $stmt->execute();

 //binding results to the query 
 $stmt->bind_result($t1,$t2);

 $boiler = array(); 

 //traversing through all the result 
 while($stmt->fetch()){
 $temp = array();

$temp['t1'] = $t1;
$temp['t2'] = $t2;

 array_push($boiler, $temp);
 }

 //displaying the result in json format 
 echo json_encode($boiler);
 ?>

java

StringRequest stringRequest1=new StringRequest(Request.Method.GET,"http://alibhm.epizy.com/fetch_turbine2.php",
            new Response.Listener<String>() {
                @Override
                public void onResponse(String response) {
                    try {
                        JSONArray array=new JSONArray(response);
                        for (int i=0; i < array.length(); i++) {
                            JSONObject product=array.getJSONObject(i);

                            String b1=product.getString("t1");
                            String b2=product.getString("t2");

                            final TextView a1=findViewById(R.id.pf1);
                            final TextView a2=findViewById(R.id.pf2);

                            a1.setText(b1);
                            a2.setText(b2);

                        }
                    } catch (JSONException e) {
                        e.printStackTrace();
                    }
                }
            },
            new Response.ErrorListener() {
                @Override
                public void onErrorResponse(VolleyError error) {
                }
            });
    Volley.newRequestQueue(this).add(stringRequest1);

StringRequest stringRequest1=新的StringRequest（Request.Method.GET）http://alibhm.epizy.com/fetch_turbine2.php",
新的Response.Listener（）{
@凌驾
公共void onResponse（字符串响应）{
试一试{
JSONArray数组=新的JSONArray（响应）；
对于（int i=0；i

一周后，我找到了答案：）我的代码没有问题。一切都是由一些免费的主机保护造成的。一些免费主机具有防机器人程序的保护。我的应用程序称为此主机的bot。我换了主人，一切都像魅力一样。我建议使用付费主机来传递问题。

您调试过吗？json字符串是否来自请求？调试以查看您得到的响应字符串，从中您可能会了解出了什么问题您是说在android studio中调试？logcat的哪一部分显示了这一点？我想我的问题来自我的主人，但为什么？我不知道。因为它在我的本地主机中工作正常