Php I';由于某种原因,我在我的一个文本框中收到了一个通知
为什么我会在referer文本框中获得以下文本: 注意:未定义索引:中的referer /var/www/register.php,第86行 以下脚本何时加载Php I';由于某种原因,我在我的一个文本框中收到了一个通知,php,Php,为什么我会在referer文本框中获得以下文本: 注意:未定义索引:中的referer /var/www/register.php,第86行 以下脚本何时加载 <?php error_reporting( E_ALL | E_STRICT ); ini_set('display_errors', 1); ?> <html> <head> <title></title> <l
<?php
error_reporting( E_ALL | E_STRICT );
ini_set('display_errors', 1);
?>
<html>
<head>
<title></title>
<link rel="icon" type="image/png" href="favicon.ico">
<?php
$err = array();
if( $_SERVER['REQUEST_METHOD']=='POST' ) {
if( empty( $_POST['display_name'] ) ) $err[] = "display name field is required";
if( empty( $_POST['email'] ) ) $err[] = "email field is required";
if( empty( $_POST['password'] ) ) $err[] = "password field is required";
if( !$err ) {
try {
$DBH = new PDO( "mysql:host=localhost;dbname=database1", "user", "pass" );
$DBH -> setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION );
$STH = $DBH -> prepare( "insert into database1.table1 (display_name, email, password) values ( :display_name, :email, :password )" );
$STH -> bindParam( ':display_name', $_POST['display_name'], PDO::PARAM_STR, 100 );
$STH -> bindParam( ':email', $_POST['email'], PDO::PARAM_STR, 100 );
$STH -> bindParam( ':password', $_POST['password'], PDO::PARAM_STR, 100 );
$STH -> execute();
if( !empty( $_POST['referer'] ) ) {
$STH = $DBH -> prepare( "insert into database1.table2 ( username, status, users_id ) values ( :username, :status, :users_id )" );
$strStatus = 1;
$STH -> bindParam( ':username', $_POST['display_name'], PDO::PARAM_STR, 100 );
$STH -> bindParam( ':status', $strStatus, PDO::PARAM_INT, 1 );
$STH -> bindParam( ':users_id', $_POST['referer'], PDO::PARAM_INT, 1 );
$STH -> execute();
}
$DBH = null;
header( "Location: ".$_SERVER['PHP_SELF'] );
exit;
} catch( PDOException $e ) {
error_log( $e -> getMessage() );
switch( $e -> getCode()) {
case 23000:
echo "Sorry, the referral ID you have entered does not exist. However, your account has been created so you can add your referral details in later.";
break;
default:
echo $e -> getMessage();
}
}
} else {
foreach( $_POST as $key => $val ) {
$form[$key] = htmlspecialchars($val);
}
}
} else {
$form['display_name'] = $form['email'] = $form['password'] = '';
}
?>
</head>
<body>
<?php
if ( isset( $err ) ) {
foreach( $err as $line ) {
echo "<div style=\"error\">".$line."</div>";
}
}
?>
<h1>register</h1>
<form method="post">
referers id:<br />
<input type="text" name="referer" value="<?php echo $form['referer']; ?>" /><br /><br />
name:<br />
<input type="text" name="display_name" value="<?php echo $form['display_name']; ?>" /><br /><br />
email:<br />
<input type="text" name="email" value="<?php echo $form['email']; ?>" /><br /><br />
password:<br />
<input type="text" name="password" value="<?php echo $form['password']; ?>" /><br /><br />
<input type="submit" value="register" />
</form>
</body>
</html>
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推荐人id:
当您第一次显示表单时,您正在执行这部分代码(第68行):
这将初始化$form
数组中的三项,这就是为什么当您尝试在第89、92和95行回显它们时,不会收到通知的原因
但是,$form
的referer
项未初始化
所以,第86行,当你尝试回显它时:
<input type="text" name="referer" value="<?php echo $form['referer']; ?>" /><br /><br />
您试图加载$form['referer'],但显然您的数组中没有'referer'条目。在第86行,将
更改为
<?php echo isset($form['referer'])?$form['referer']:''; ?>
-编辑-感谢Pascal MARTIN的评论,这是正确的您应该在脚本顶部初始化$\u POST['referer'],以避免这些错误。在第63行,他用$\u POST
值填充$\form
表单,这样表单就可以在那里了。@rsplak表单提交时;但是在第一次显示时(在提交表单之前,当表单显示给用户以便他们可以提交表单时),第63行没有执行。在这种情况下,您仍在尝试读取$form['referer']
,因此您仍然会收到通知--您需要使用isset()
来测试是否设置了项。
<?php echo $form['referer']; ?>
<?php echo isset($form['referer'])?$form['referer']:''; ?>