Php SQL联接和工作不正常
我在生成查询结果时遇到问题。我想从与主表相关的另一个表中生成行结果的总和 我没有输出的是付款总额和应付款项总额Php SQL联接和工作不正常,php,mysql,codeigniter,Php,Mysql,Codeigniter,我在生成查询结果时遇到问题。我想从与主表相关的另一个表中生成行结果的总和 我没有输出的是付款总额和应付款项总额 问题#1-我无法生成正确的付款输出。这个 查询似乎产生了一个numrows*付款总额的公式 问题#2-我无法生成应付款总额的输出 我正在使用Codeigniter 3,这是我的模型 function fetch_billing_records($case_id, $patient_id, $status) { $this->db->join('case
- 问题#1-我无法生成正确的付款输出。这个
查询似乎产生了一个
numrows*付款总额的公式
- 问题#2-我无法生成应付款总额的输出
function fetch_billing_records($case_id, $patient_id, $status) {
$this->db->join('cases', 'cases.id = billing.case_id', 'left');
$this->db->join('patients', 'patients.id = cases.patient_id', 'left');
$this->db->join('users', 'users.username = billing.user', 'left');
$this->db->join('billing_payments', 'billing_payments.billing_id = billing.id', 'left');
$this->db->join('billing_items', 'billing_items.billing_id = billing.id', 'left');
$this->db->join('services', 'services.title = billing_items.service', 'left');
$this->db->select('
billing.id,
billing.remarks,
billing.status,
billing.created_at,
billing.updated_at,
users.name as user,
users.username,
cases.id as case_id,
cases.title as case_title,
patients.id as patient_id,
CONCAT(patients.lastname, ", ", patients.fullname) as patient_name,
SUM(billing_payments.amount) as payments,
SUM((services.amount - billing_items.discount)*billing_items.qty) as payables
');
if(is_int($case_id)) {
$this->db->where('billing.case_id', $case_id);
}
if(is_int($patient_id)) {
$this->db->where('patients.id', $patient_id);
}
if(is_int($status)) {
$this->db->where('billing.status', $status);
}
$this->db->group_by('billing.id');
$this->db->where('billing.is_deleted', 0);
$query = $this->db->get("billing");
log_message('error', $this->db->last_query());
if ($query->num_rows() > 0) {
return $query->result_array();
}
return false;
}
我用最后一个查询和日志助手保存了最后一个查询,我的实例的查询似乎是
SELECT `billing`.`id`, `billing`.`remarks`, `billing`.`status`, `billing`.`created_at`, `billing`.`updated_at`, `users`.`name` as `user`, `users`.`username`, `cases`.`id` as `case_id`, `cases`.`title` as `case_title`, `patients`.`id` as `patient_id`, CONCAT(patients.lastname, ", ", patients.fullname) as patient_name, SUM(billing_payments.amount) as payments, SUM((services.amount - billing_items.discount)*billing_items.qty) as payables
FROM `billing`
LEFT JOIN `cases` ON `cases`.`id` = `billing`.`case_id`
LEFT JOIN `patients` ON `patients`.`id` = `cases`.`patient_id`
LEFT JOIN `users` ON `users`.`username` = `billing`.`user`
LEFT JOIN `billing_payments` ON `billing_payments`.`billing_id` = `billing`.`id`
LEFT JOIN `billing_items` ON `billing_items`.`billing_id` = `billing`.`id`
LEFT JOIN `services` ON `services`.`title` = `billing_items`.`service`
WHERE `billing`.`is_deleted` =0
为了更好地指导您解决我目前的问题,以下是相关表的架构:
这是整个数据库的模式
使用group by语句。因为mysql聚合函数可以很好地与GROUPBY配合使用。如果您想要针对患者的账单金额,则使用以下查询
SELECT
`billing`.`id`,
`billing`.`remarks`,
`billing`.`status`,
`billing`.`created_at`,
`billing`.`updated_at`, `
users`.`name` as `user`,
`users`.`username`,
`cases`.`id` as `case_id`,
`cases`.`title` as `case_title`,
`patients`.`id` as `patient_id`,
CONCAT(patients.lastname, ", ", patients.fullname) as patient_name,
SUM(billing_payments.amount) as payments,
SUM((services.amount - billing_items.discount)*billing_items.qty) as payables
FROM `billing`
LEFT JOIN `cases` ON `cases`.`id` = `billing`.`case_id`
LEFT JOIN `patients` ON `patients`.`id` = `cases`.`patient_id`
LEFT JOIN `users` ON `users`.`username` = `billing`.`user`
LEFT JOIN `billing_payments` ON `billing_payments`.`billing_id` = `billing`.`id`
LEFT JOIN `billing_items` ON `billing_items`.`billing_id` = `billing`.`id`
LEFT JOIN `services` ON `services`.`title` = `billing_items`.`service`
WHERE `billing`.`is_deleted` =0
GROUP BY patients.id
使用GROUPBY语句。因为mysql聚合函数可以很好地与GROUPBY配合使用。如果您想要针对患者的账单金额,则使用以下查询
SELECT
`billing`.`id`,
`billing`.`remarks`,
`billing`.`status`,
`billing`.`created_at`,
`billing`.`updated_at`, `
users`.`name` as `user`,
`users`.`username`,
`cases`.`id` as `case_id`,
`cases`.`title` as `case_title`,
`patients`.`id` as `patient_id`,
CONCAT(patients.lastname, ", ", patients.fullname) as patient_name,
SUM(billing_payments.amount) as payments,
SUM((services.amount - billing_items.discount)*billing_items.qty) as payables
FROM `billing`
LEFT JOIN `cases` ON `cases`.`id` = `billing`.`case_id`
LEFT JOIN `patients` ON `patients`.`id` = `cases`.`patient_id`
LEFT JOIN `users` ON `users`.`username` = `billing`.`user`
LEFT JOIN `billing_payments` ON `billing_payments`.`billing_id` = `billing`.`id`
LEFT JOIN `billing_items` ON `billing_items`.`billing_id` = `billing`.`id`
LEFT JOIN `services` ON `services`.`title` = `billing_items`.`service`
WHERE `billing`.`is_deleted` =0
GROUP BY patients.id
你有没有把没有分组的select sum放在可能的地方?@martonohalim我有
$this->db->group_by('billing.id')代码>我不确定代码点火器是如何工作的,但您的分组方式似乎没有足够的列来分组。它应该放置除sum列之外的所有列。希望有帮助。@AaronAlfonso试着把false
像$this->db->select(“你选择的部分”,false)代码>似乎使用codeigniter进行选择没有问题。问题是对SQL的正确查询。您是否在没有分组依据的情况下输入了select sum?@martonohalim I did$this->db->group_by('billing.id')代码>我不确定代码点火器是如何工作的,但您的分组方式似乎没有足够的列来分组。它应该放置除sum列之外的所有列。希望有帮助。@AaronAlfonso试着把false
像$this->db->select(“你选择的部分”,false)代码>似乎使用codeigniter进行选择没有问题。问题是SQL的正确查询。根据我的实例的要求,我做了一个$this->db->group\u by('billing.id')
。但是我知道确实需要group byYes。但我试图通过命令行执行,但它有相同的输出。我相信我需要知道的是正确地查询SQLwhat result you want?我按照我的实例的要求做了一个$this->db->group\u by('billing.id')
。但是我知道确实需要group byYes。但我试图通过命令行执行,但它有相同的输出。我相信我需要知道的是正确查询SQLServer,您想要什么结果?