Playframework Play2.0框架中是否允许最大数量的表?
您好,我创建了一个快速表格:Playframework Play2.0框架中是否允许最大数量的表?,playframework,playframework-2.0,Playframework,Playframework 2.0,您好,我创建了一个快速表格: package models; import javax.persistence.*; import play.db.ebean.Model; @Entity public class Phone extends Model { @Id public Long phoneID; public String group; public String name; } 我得到以下错误: PersistenceException:获取序列nextval时出错 javax
package models;
import javax.persistence.*;
import play.db.ebean.Model;
@Entity
public class Phone extends Model {
@Id
public Long phoneID;
public String group;
public String name;
}
我得到以下错误:
PersistenceException:获取序列nextval时出错
javax.persistence.PersistenceException:获取序列nextval时出错
com.avaje.ebean.config.dbplatform.SequenceIdGenerator.getMoreIds(SequenceIdGenerator.java:213)
com.avaje.ebean.config.dbplatform.SequenceIdGenerator.loadMoreIds(SequenceIdGenerator.java:163)
com.avaje.ebean.config.dbplatform.SequenceIdGenerator.nextId(SequenceIdGenerator.java:118)
com.avaje.ebeaninternal.server.deploy.BeanDescriptor.nextId(BeanDescriptor.java:1218)
com.avaje.ebeaninternal.server.persist.DefaultPersister.setIdGenValue(DefaultPersister.java:1304)
com.avaje.ebeaninternal.server.persist.DefaultPersister.insert(DefaultPersister.java:403)
com.avaje.ebeaninternal.server.persist.DefaultPersister.saveEnhanced(DefaultPersister.java:345)
com.avaje.ebeaninternal.server.persist.DefaultPersister.saveRecurse(DefaultPersister.java:315)
com.avaje.ebeaninternal.server.persist.DefaultPersister.save(DefaultPersister.java:282)
com.avaje.ebeaninternal.server.core.DefaultServer.save(DefaultServer.java:1577)
com.avaje.ebeaninternal.server.core.DefaultServer.save(DefaultServer.java:1567)
save(ebean.java:538)play.db.ebean.Model.save(Model.java:76)
models.Command.createCommand(Command.java:100)
models.Command.populateCommands(Command.java:68)
Global.onStart(Global.java:22)play.core.j.JavaGlobalSettingsAdapter.onStart(javaglobalsettingsapter.scala:15)
play.api.GlobalPlugin.onStart(Global.scala:134)
play.api.play$$anonfun$start$1.apply(play.scala:60)
play.api.play$$anonfun$start$1.apply(play.scala:60)
scala.collection.LinearSeqOptimized$class.foreach(LinearSeqOptimized.scala:59)
scala.collection.immutable.List.foreach(List.scala:45)
play.api.play$.start(play.scala:60)
play.core.ReloadableApplication$$anonfun$get$1$$anonfun$apply$3$$anonfun$1.apply(ApplicationProvider.scala:125)
play.core.ReloadableApplication$$anonfun$get$1$$anonfun$apply$3$$anonfun$1.apply(ApplicationProvider.scala:112)
scala.Option.map(Option.scala:133)
play.core.ReloadableApplication$$anonfun$get$1$$anonfun$apply$3.apply(ApplicationProvider.scala:112)
play.core.ReloadableApplication$$anonfun$get$1$$anonfun$apply$3.apply(ApplicationProvider.scala:110)
scala.any$RightProjection.flatMap(any.scala:277)
play.core.ReloadableApplication$$anonfun$get$1.apply(ApplicationProvider.scala:110)
play.core.ReloadableApplication$$anonfun$get$1.apply(ApplicationProvider.scala:110)
akka.dispatch.Future$$anon$3.liftedTree1$1(Future.scala:195)
akka.dispatch.Future$$anon$3.run(Future.scala:194)
akka.dispatch.TaskInvocation.run(AbstractDispatcher.scala:83)
akka.jsr166y.ForkJoinTask$AdaptedRunnableAction.exec(ForkJoinTask.java:1381)
akka.jsr166y.ForkJoinTask.doExec(ForkJoinTask.java:259)
akka.jsr166y.ForkJoinPool$WorkQueue.runTask(ForkJoinPool.java:974)
akka.jsr166y.ForkJoinPool.runWorker(ForkJoinPool.java:1478)
akka.jsr166y.ForkJoinWorkerThread.run(ForkJoinWorkerThread.java:104)
使用h2内存数据库是否有允许的最大表数?我真的不明白这个错误是从哪里来的。如果我删除这一行,它可以正常工作,但它看起来像是另一个类导致了问题:createCommand,它只有以下内容:
public static void create(Command data) {
data.save();
}
public static void populateCommands() {
createCommand(0x00, "Cmd1");
createCommand(0x02, "Cmd2");
createCommand(0x03, "Cmd3");
}
感谢您的帮助。我想问题是我打开了eclipse。 我注意到eclipse和play同时运行时存在一些问题。
我需要关闭eclipse运行play框架并再次打开eclipse。
group
是大多数数据库中的一个关键字,所以请将其名称更改为phonesGroup或其他名称。