Postgresql：选择具有不同条件的总和

我有两张桌子：

一、表1如下：

------------------------------------------
codeid | pos   | neg   | category 
-----------------------------------------
   1   | 10    |  3    | begin2016
   1   |  3    |  5    |  justhere
   3   |  7    |  7    |  justthere
   4   |  1    |  1    |  else
   4   | 12    |  0    |  begin2015
   4   |  5    |  12   |  begin2013
   1   |  2    |  50   |  now
   2   |  5    |  33   |  now
   5   |  33   |   0   |  Begin2011
   5   |  11   |   7   |  begin2000

------------------------------------------
codeid | codedesc         | codegroupid 
-----------------------------------------
1      |  road runner     |    1
2      |  bike warrior    |    2
3      |  lazy driver     |    4
4      |  clever runner   |    1
5      |  worker          |    3
6      |  smarty          |    1
7      |  sweety          |    3
8      |  sweeper         |    1

------------------------------------------
codeid |      codedesc     | sumpos | sumneg
-----------------------------------------
 1   |  roadrunner       |  5     |  55   => (sumpos = 3+2, because 10 have category like 'begin%' so doesn't sum) 
 2   |  bike warrior     |  5     |  33
 4   |  clever runner    |  1     |  1
 5   |  worker           |  0     |  0   => (sumpos=sumneg=0) becase codeid 5 category ilike 'begin%'

二,。表2如下所示：

------------------------------------------
codeid | pos   | neg   | category 
-----------------------------------------
   1   | 10    |  3    | begin2016
   1   |  3    |  5    |  justhere
   3   |  7    |  7    |  justthere
   4   |  1    |  1    |  else
   4   | 12    |  0    |  begin2015
   4   |  5    |  12   |  begin2013
   1   |  2    |  50   |  now
   2   |  5    |  33   |  now
   5   |  33   |   0   |  Begin2011
   5   |  11   |   7   |  begin2000

------------------------------------------
codeid | codedesc         | codegroupid 
-----------------------------------------
1      |  road runner     |    1
2      |  bike warrior    |    2
3      |  lazy driver     |    4
4      |  clever runner   |    1
5      |  worker          |    3
6      |  smarty          |    1
7      |  sweety          |    3
8      |  sweeper         |    1

------------------------------------------
codeid |      codedesc     | sumpos | sumneg
-----------------------------------------
 1   |  roadrunner       |  5     |  55   => (sumpos = 3+2, because 10 have category like 'begin%' so doesn't sum) 
 2   |  bike warrior     |  5     |  33
 4   |  clever runner    |  1     |  1
 5   |  worker           |  0     |  0   => (sumpos=sumneg=0) becase codeid 5 category ilike 'begin%'

我希望有一个这样的结果，有两个（或更多）条件：

pos和neg之和，其中codegroupid位于（'1'，'2'，'3'）

但如果类别为“开始%”，则不要求正和负之和

因此，结果如下所示：

------------------------------------------
codeid | pos   | neg   | category 
-----------------------------------------
   1   | 10    |  3    | begin2016
   1   |  3    |  5    |  justhere
   3   |  7    |  7    |  justthere
   4   |  1    |  1    |  else
   4   | 12    |  0    |  begin2015
   4   |  5    |  12   |  begin2013
   1   |  2    |  50   |  now
   2   |  5    |  33   |  now
   5   |  33   |   0   |  Begin2011
   5   |  11   |   7   |  begin2000

------------------------------------------
codeid | codedesc         | codegroupid 
-----------------------------------------
1      |  road runner     |    1
2      |  bike warrior    |    2
3      |  lazy driver     |    4
4      |  clever runner   |    1
5      |  worker          |    3
6      |  smarty          |    1
7      |  sweety          |    3
8      |  sweeper         |    1

------------------------------------------
codeid |      codedesc     | sumpos | sumneg
-----------------------------------------
 1   |  roadrunner       |  5     |  55   => (sumpos = 3+2, because 10 have category like 'begin%' so doesn't sum) 
 2   |  bike warrior     |  5     |  33
 4   |  clever runner    |  1     |  1
 5   |  worker           |  0     |  0   => (sumpos=sumneg=0) becase codeid 5 category ilike 'begin%'

按codeid、codedesc分组
Sumpos是sum（pos），其中类别不象“begin%”，但如果类别ILKIE“begin%”使所有pos值变为零（0）
Sumpos是sum（neg），其中类别不象“begin%”，但如果类别ILKIE“begin%”使所有的neg值变为零

有什么办法吗

试试看：

SELECT
    b.codeid,
    b.codedesc,
    sum(CASE WHEN category LIKE 'begin%' THEN 0 ELSE a.pos END) AS sumpos,
    sum(CASE WHEN category LIKE 'begin%' THEN 0 ELSE a.neg END) AS sumneg
FROM
    table1 AS a
    JOIN
    table2 AS b ON a.codeid = b.codeid
WHERE b.codegroupid IN (1, 2, 3)
GROUP BY
    b.codeid,
    b.codedesc;

---

结果是否应该包含所有代码ID（1-8）的记录？我想也许您只需要codegroupid=1或2的记录，但您的结果是显示worker（codegroupid=3）。不清楚您的结果集是否只是显示子集。很抱歉，我已将coudegroupid编辑为1、2或3。非常感谢。