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Python 2.7 matplotlib:散点图不能';t连接点_Python 2.7_Pandas_Matplotlib - Fatal编程技术网

Python 2.7 matplotlib:散点图不能';t连接点

Python 2.7 matplotlib:散点图不能';t连接点,python-2.7,pandas,matplotlib,Python 2.7,Pandas,Matplotlib,我正在使用以下代码绘制散点图,并尝试连接图中的点: %matplotlib notebook import matplotlib.pyplot as plt import matplotlib matplotlib.style.use('ggplot') my_df.plot(x='k', y='score', kind = 'scatter', marker = 'x', linestyle='-') 还尝试: my_df.plot(x='k',

我正在使用以下代码绘制散点图,并尝试连接图中的点:

   %matplotlib notebook
    import matplotlib.pyplot as plt
    import matplotlib
    matplotlib.style.use('ggplot')
    my_df.plot(x='k', y='score', kind = 'scatter', marker = 'x', linestyle='-')
还尝试:

    my_df.plot(x='k', y='score', kind = 'scatter', 'xb-')

但上述两项都不起作用。有人知道我错过了什么吗?谢谢

更改您的
标记
kwag,并移除
种类
kwag:

my_df.plot(x='k', y='score', marker='x-')
# removing linestyle is optional. It does not help in this case

经过一些实验,下面的代码可以工作:

%matplotlib notebook
import matplotlib.pyplot as plt
import matplotlib
matplotlib.style.use('ggplot')
my_df.plot(x='k', y='score', marker = 'x', color = 'black')

请给出一个工作示例。我的_df是什么?然后我得到了错误:ValueError:unrecogned marker style x-