Python 2.7 在python中从多组括号之间的字符串中提取文本

如果字符串=

Firstname Lastname(email1@place.edu)Firstname2 Lastname2(email2@place.edu)

我想创建一个新的字符串

email1@place.edu,email2@place.edu

我试过了

string= string.partition('(')[-1].partition(')')[0]

但是我得到了

email1@place.edu)Firstname2 Lastname2(email2@place.edu

我怎样才能分开这根绳子

string.split()

您可以通过传递一个参数来告诉Python您想要使用的

split（）

split（）

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编辑：

如果您只是试图访问带括号的字符串，那么可以使用正则表达式或python的

使用正则表达式

import re 
regexp_pattern = '\([^\(\r\n]*\)'
st = "Firstname Lastname (email1@place.edu) Firstname2 Lastname2 (email2@place.edu)"
a = re.findall(regexp_pattern, st) #this gives you the list ['(email1@place.edu)','(email2@place.edu)']
b = ''.join(a)[1:-1] #this gives you the string 'email1@place.edu)(email2@place.edu'
b.replace(")(", ",") #this gives you the string 'email1@place.edu,email2@place.edu'

当然，如果你更喜欢，你可以做得更短（我喜欢）：

import re 
regexp_pattern = '\([^\(\r\n]*\)'
st = "Firstname Lastname (email1@place.edu) Firstname2 Lastname2 (email2@place.edu)"
a = re.findall(regexp_pattern, st) #this gives you the list ['(email1@place.edu)','(email2@place.edu)']
b = ''.join(a)[1:-1] #this gives you the string 'email1@place.edu)(email2@place.edu'
b.replace(")(", ",") #this gives you the string 'email1@place.edu,email2@place.edu'

import re 
regexp_pattern = '\([^\(\r\n]*\)'
st = "Firstname Lastname (email1@place.edu) Firstname2 Lastname2 (email2@place.edu)"
''.join(re.findall(regexp_pattern, st))[1:-1].replace(")(", ",")