Python 3.x 如何添加标题和对齐列表

我有这个数据集，我需要对齐

ID

、

Date

和

Title

的列。我不知道如何对齐这些和如何添加标题？我无法使用任何第三方功能，如

制表

。有人能告诉我怎么做吗？我是初学者，只是需要一些指导

data_set = [['ID=j234hg\n'], ['Date=19 October 1969\n'], ['Title=court scene with cardinal richelieu\n'], ['ID=d45j5jkd\n'], ['Date=28 December 1969\n'], ['Title=THE ROYAL PHILHARMONIC ORCHESTRA GOES TO THE BATHROOM\n'], ['ID=s4k5jk\n'], ['Date=8 December 1970\n'], ['Title=crossing the atlantic on a tricycle\n'], ['ID=zd7u4h\n'], ['Date=19 October 1969\n'], ['Title=Bicycle Repair Man\n'], ['ID=f983\n'], ['Date=22 December 1970\n'], ['Title=Royal Episode 13 (or: The Queen Will Be Watching)\n'], ['ID=j8s74\n'], ['Date=15 September 1970\n'], ['Title=THE SEMAPHORE VERSION OF WUTHERING HEIGHTS\n'], ['ID=n4j6l3j\n'], ['Date=7 December 1972\n'], ['Title=Mr. Pither']]

它需要如下所示：

#ID       Date              Title
#d45j5jkd 28 December 1969  The Royal Philharmonic Orchestra Goes To The Bathroom
#f983     22 December 1970  Royal Episode 13 (Or: The Queen Will Be Watching)

您可以使用格式化和对齐标题和

数据集

不幸的是，

数据集

是一个由子

列表

组成的

列表

，因此它开始时有点混乱，然后在

for

循环中打印，用于从展开列表中打印3组：

data_set = [['ID=j234hg\n'], ['Date=19 October 1969\n'], ['Title=court scene with cardinal richelieu\n'], 
        ['ID=d45j5jkd\n'], ['Date=28 December 1969\n'], ['Title=THE ROYAL PHILHARMONIC ORCHESTRA GOES TO THE BATHROOM\n'], 
        ['ID=s4k5jk\n'], ['Date=8 December 1970\n'], ['Title=crossing the atlantic on a tricycle\n'], 
        ['ID=zd7u4h\n'], ['Date=19 October 1969\n'], ['Title=Bicycle Repair Man\n'], ['ID=f983\n'], 
        ['Date=22 December 1970\n'], ['Title=Royal Episode 13 (or: The Queen Will Be Watching)\n'], 
        ['ID=j8s74\n'], ['Date=15 September 1970\n'], ['Title=THE SEMAPHORE VERSION OF WUTHERING HEIGHTS\n'], 
        ['ID=n4j6l3j\n'], ['Date=7 December 1972\n'], ['Title=Mr. Pither']]

#First, flatten the list of lists to one list of strings
flist = [item for sublist in data_set for item in sublist]

print('{h1:10}{h2:20}{h3}'.format(h1='#ID', h2='Date', h3='Title'))
for i in range(0, len(flist), 3):
    print('{id:10}{date:20}{title}'   
                       .format(   
                               id=flist[i].strip('\n').split('=')[1],   
                               date=flist[i+1].strip('\n').split('=')[1],   
                               title=flist[i+2].strip('\n').split('=')[1])
                              )

输出：

#ID       Date                Title
j234hg    19 October 1969     court scene with cardinal richelieu
d45j5jkd  28 December 1969    THE ROYAL PHILHARMONIC ORCHESTRA GOES TO THE BATHROOM
s4k5jk    8 December 1970     crossing the atlantic on a tricycle
zd7u4h    19 October 1969     Bicycle Repair Man
f983      22 December 1970    Royal Episode 13 (or: The Queen Will Be Watching)
j8s74     15 September 1970   THE SEMAPHORE VERSION OF WUTHERING HEIGHTS
n4j6l3j   7 December 1972     Mr. Pither

如果它不能准确回答您的问题，请随时发表评论。

---

我很抱歉，因为这是非常混乱，但它的工作。我稍后会把它清理干净。同时，我希望这能有所帮助

当我把这个放进去的时候，它似乎不想接受。我必须再次查看错误，但它表明.strip部分出现了问题。抱歉，是的，我没想到您第一次尝试它时它会完美工作，因为它有点凌乱。如果您愿意，请随时发布您遇到的任何错误，我可以尝试修改代码以使其适合您。感谢您的反馈。另外，请确保

数据集

的结构与您在问题中提到的相同，即

[[[''ID=j234hg\n']，[''.\n']，['.\n']，[''.\n']，['Title=Mr.Pither']

-a

列表的
列表
flist=[data\u set]打印（'{h1:10}{h2:20}{h3}格式（h1='#ID'，h2='Date'，h3='Title'））范围内的i（0，len（flist），3）：打印（'{ID:10}{Date:20}{Title}）。格式（ID=flist[i]。strip（'\n'）。split（'='）[1]，Date=flist[i+1]。strip（'\n'）。split（'='））[1]，title=flist[i+2].strip（'\n'）.split（'='）[1]）我以您的格式将其输入到我的代码中，它给了我：
#ID       Date                Title
j234hg    19 October 1969     court scene with cardinal richelieu
d45j5jkd  28 December 1969    THE ROYAL PHILHARMONIC ORCHESTRA GOES TO THE BATHROOM
s4k5jk    8 December 1970     crossing the atlantic on a tricycle
zd7u4h    19 October 1969     Bicycle Repair Man
f983      22 December 1970    Royal Episode 13 (or: The Queen Will Be Watching)
j8s74     15 September 1970   THE SEMAPHORE VERSION OF WUTHERING HEIGHTS
n4j6l3j   7 December 1972     Mr. Pither