Python 3.x Pandas使用跨行条件统计每月发生的事件
我有一个这样的数据帧Python 3.x Pandas使用跨行条件统计每月发生的事件,python-3.x,pandas,dataframe,datetime,data-analysis,Python 3.x,Pandas,Dataframe,Datetime,Data Analysis,我有一个这样的数据帧 oper_status 2012-01-01 00:26:54.250 0 2012-01-01 12:11:54.250 1 2012-01-01 13:57:54.250 2 2012-01-02 00:16:54.250 0 2012-01-02 14:26:54.250 1 2012-01-02 1
oper_status
2012-01-01 00:26:54.250 0
2012-01-01 12:11:54.250 1
2012-01-01 13:57:54.250 2
2012-01-02 00:16:54.250 0
2012-01-02 14:26:54.250 1
2012-01-02 17:20:54.250 0
2012-01-04 08:21:54.250 0
2012-01-04 15:34:54.250 1
2012-01-04 19:45:54.250 0
2012-01-05 01:00:54.250 0
2012-01-05 12:46:54.250 1
2012-01-05 20:27:54.250 2
(...) (...)
count
time
2012-03-31 244
2012-04-30 65
2012-05-31 167
2012-06-30 33
2012-07-31 187
... ...
2013-05-31 113
2013-06-30 168
2013-07-31 294
2013-08-31 178
2013-09-30 65
我想计算每个月我有多少次连续的值是这样的:0,1,2。
我尝试使用iterrows()在行上循环,但速度非常慢,因为我有一个大数据集。
我也考虑过使用“diff”,但我想不出一个简单的方法。谢谢
编辑:
预期输出如下所示
oper_status
2012-01-01 00:26:54.250 0
2012-01-01 12:11:54.250 1
2012-01-01 13:57:54.250 2
2012-01-02 00:16:54.250 0
2012-01-02 14:26:54.250 1
2012-01-02 17:20:54.250 0
2012-01-04 08:21:54.250 0
2012-01-04 15:34:54.250 1
2012-01-04 19:45:54.250 0
2012-01-05 01:00:54.250 0
2012-01-05 12:46:54.250 1
2012-01-05 20:27:54.250 2
(...) (...)
count
time
2012-03-31 244
2012-04-30 65
2012-05-31 167
2012-06-30 33
2012-07-31 187
... ...
2013-05-31 113
2013-06-30 168
2013-07-31 294
2013-08-31 178
2013-09-30 65
计算顺序模式是一个两步过程。首先,为每行构建一个序列,表示在该行结束的模式:
df['seq'] = df.order_status.astype(str).shift(periods=0) + '-' +
df.order_status.astype(str).shift(periods=1) + '-' +
df.order_status.astype(str).shift(periods=2)
date order_status seq
0 2012-01-01 00:26:54.250 0 NaN
1 2012-01-01 12:11:54.250 1 NaN
2 2012-01-01 13:57:54.250 2 2-1-0
3 2012-01-02 00:16:54.250 0 0-2-1
4 2012-01-02 14:26:54.250 1 1-0-2
5 2012-01-02 17:20:54.250 0 0-1-0
6 2012-01-04 08:21:54.250 0 0-0-1
7 2012-01-04 15:34:54.250 1 1-0-0
8 2012-01-04 19:45:54.250 0 0-1-0
9 2012-01-05 01:00:54.250 0 0-0-1
10 2012-01-05 12:46:54.250 1 1-0-0
11 2012-01-05 20:27:54.250 2 2-1-0
然后,只过滤到正确的序列,并聚合到所需的级别:
df['month'] = df.date.dt.month
df[df.seq == '2-1-0'].groupby("month").month.count()
month
1 2
根据需要进行更改,以处理您希望模式在某个时间段内开始、停止、完全在某个时间段内等情况。类似于?另外,您使用的是Python3还是Python2?你问题的标签在这方面是不明确的…请显示预期的输出,但这不是我的意思。我需要的东西,计算多少时间,我有0,1,2(在连续三行)。我删除了python 2,谢谢