Python 3.x Python 3：如何在不停止函数的情况下退出循环

我是一个完全的新手，在过去的5个小时里，我一直在尝试解决这个问题（用我自己的头脑和在线研究）

下面是我们为模拟游戏而编写的函数的一个片段。我们想提供一个开始新一轮的机会-这意味着如果一个玩家点击“b”，游戏应该在范围的开始（0，玩家）重新开始。但现在它只是进入范围内的下一个玩家（如果玩家1进入“b”，程序调用玩家2）

我试过回击和断球，也试过把它放在另一个while循环中。。。失败。Break和return刚刚结束了函数。

---

任何提示都非常感谢

您可以将

for

循环更改为

while

循环。不要使用

范围

，而是将

播放器

设为计数器

players = 4
if 3 <= players < 9:  
    player = 0  # here's where you make your counter
    while player < players:
        sum_points = 0
        throw_per_player_counter = 0
        print("\nIt is player no.", player+1, "'s turn!\n")
        print("\nPress 'return' to roll the dice.\n"
              "To start a new round press 'b'.\n"
              "Player", player+1)
        roll_dice = input(">>> ")
        player += 1  # increment it
        if roll_dice == "b":
            player = 0  # now your reset should work
            throw_per_player_counter = 0
            sum_points = 0
            print("\n * A new round was started. * \n")

players=4
如果3>”）
玩家+=1#增加它
如果掷骰子=“b”：
player=0#现在您的重置应该可以工作了
每名玩家掷骰次数=0
总和=0
打印（“\n*新一轮已开始。*\n”）

谢谢！这确实有助于打破循环！一些测试用例的总分数失败了（显然这是不应该的加倍分数））我注意到这里有很多

player+1

，这很容易成为错误和计算错误的原因。变量并不代表实际值。因为

player

代表一个以

1

开头的玩家号，所以可能值得重新计算-写入以使

player

变量一致地反映其实际值。

player=1

，

而player
players = 4
if 3 <= players < 9:  
    player = 0  # here's where you make your counter
    while player < players:
        sum_points = 0
        throw_per_player_counter = 0
        print("\nIt is player no.", player+1, "'s turn!\n")
        print("\nPress 'return' to roll the dice.\n"
              "To start a new round press 'b'.\n"
              "Player", player+1)
        roll_dice = input(">>> ")
        player += 1  # increment it
        if roll_dice == "b":
            player = 0  # now your reset should work
            throw_per_player_counter = 0
            sum_points = 0
            print("\n * A new round was started. * \n")