将包含python src文件的目录作为模块导入

我有一个关于将python目录foo作为模块导入的问题。结构如下：

--

foo

--

\uuuu init\uuuuu.py

---

file1.py

---

file2.py

\uuuu init\uuuu.py

包含以下行：

\uuuuu all\uuuuu=[“文件1”、“文件2”]

我想做的是导入foo，然后以

foo.file1

但是，我只能在执行以下操作后访问

file1

：

来自foo导入*

我可以通过

foo.file1

访问file1，它是：

来自foo导入*

导入foo

正如你所看到的，这是相当低效的。有人能告诉我，做我想做的事情的正确方法是什么吗

谢谢

这正是\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu。如果您希望能够执行

foo.file1

，而不是使用

\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu

import file1