python更改行的列

python更改行的列,python,dataframe,interpolation,Python,Dataframe,Interpolation,我只看到过与我在这里寻找的相反的帖子。使用jupyter笔记本/python,我从csv文件导入了第一个块,我想要第二个块: Country | 1990 | 1991 | 1992 | ---------------------------------- | Albania | 1.0 | 1.2 | 2.6 | | Algeria | 2.0 | 2.3 | 3.3 | | Andora | 1.5 | 6.9 | 5.3 | Country

我只看到过与我在这里寻找的相反的帖子。使用jupyter笔记本/python,我从csv文件导入了第一个块,我想要第二个块:

    Country | 1990 | 1991 | 1992 |
 ----------------------------------
  | Albania |   1.0 | 1.2 | 2.6 |
  | Algeria |   2.0 | 2.3 | 3.3 |
  | Andora  |   1.5 | 6.9 | 5.3 |


   Country   | Year | Value | 
 ------------------------------
  | Albania  | 1990 |  1.0  | 
  | Albania  | 1991 |  1.2  | 
  | Albania  | 1992 |  2.6  | 
  | Algeria  | 1990 |  2.0  | 
  | Algeria  | 1990 |  2.3  | 
  | Algeria  | 1990 |  3.3  | 
etc.
我是python新手,不确定是否需要使用pandas、numpy以及哪些函数(pivot_table、re index、interpolate)。
谢谢

试试这个:

import pandas as pd

df = pd.read_csv('my-csv.csv')
new_df = df.set_index('Country').stack()
试试这个:

import pandas as pd

df = pd.read_csv('my-csv.csv')
new_df = df.set_index('Country').stack()

熊猫的融化功能就可以了

import pandas as pd

df = pd.DataFrame({'Year': [1990 , 1991 , 1992], 'Albania': [1.0 , 1.2 , 2.6 ],'Algeria':[2.0,2.3,3.3],"Andora":[1.5,6.9,5.3]})



print df
          Albania  Algeria  Andora  Year
    0      1.0      2.0     1.5  1990
    1      1.2      2.3     6.9  1991
    2      2.6      3.3     5.3  1992
melted = pd.melt(df, id_vars=["Year"],
                 var_name="Country", value_name="Score")
print melted

   Year  Country  Score
0  1990  Albania    1.0
1  1991  Albania    1.2
2  1992  Albania    2.6
3  1990  Algeria    2.0
4  1991  Algeria    2.3
5  1992  Algeria    3.3
6  1990   Andora    1.5
7  1991   Andora    6.9

8  1992   Andora    5.3
熔体重塑df(关于年)

import pandas as pd

df = pd.DataFrame({'Year': [1990 , 1991 , 1992], 'Albania': [1.0 , 1.2 , 2.6 ],'Algeria':[2.0,2.3,3.3],"Andora":[1.5,6.9,5.3]})



print df
          Albania  Algeria  Andora  Year
    0      1.0      2.0     1.5  1990
    1      1.2      2.3     6.9  1991
    2      2.6      3.3     5.3  1992
melted = pd.melt(df, id_vars=["Year"],
                 var_name="Country", value_name="Score")
print melted

   Year  Country  Score
0  1990  Albania    1.0
1  1991  Albania    1.2
2  1992  Albania    2.6
3  1990  Algeria    2.0
4  1991  Algeria    2.3
5  1992  Algeria    3.3
6  1990   Andora    1.5
7  1991   Andora    6.9

8  1992   Andora    5.3
我搞乱了你的df,你的案子也一样。
更多关于熔化的信息-->

熊猫的熔化功能就可以了

import pandas as pd

df = pd.DataFrame({'Year': [1990 , 1991 , 1992], 'Albania': [1.0 , 1.2 , 2.6 ],'Algeria':[2.0,2.3,3.3],"Andora":[1.5,6.9,5.3]})



print df
          Albania  Algeria  Andora  Year
    0      1.0      2.0     1.5  1990
    1      1.2      2.3     6.9  1991
    2      2.6      3.3     5.3  1992
melted = pd.melt(df, id_vars=["Year"],
                 var_name="Country", value_name="Score")
print melted

   Year  Country  Score
0  1990  Albania    1.0
1  1991  Albania    1.2
2  1992  Albania    2.6
3  1990  Algeria    2.0
4  1991  Algeria    2.3
5  1992  Algeria    3.3
6  1990   Andora    1.5
7  1991   Andora    6.9

8  1992   Andora    5.3
熔体重塑df(关于年)

import pandas as pd

df = pd.DataFrame({'Year': [1990 , 1991 , 1992], 'Albania': [1.0 , 1.2 , 2.6 ],'Algeria':[2.0,2.3,3.3],"Andora":[1.5,6.9,5.3]})



print df
          Albania  Algeria  Andora  Year
    0      1.0      2.0     1.5  1990
    1      1.2      2.3     6.9  1991
    2      2.6      3.3     5.3  1992
melted = pd.melt(df, id_vars=["Year"],
                 var_name="Country", value_name="Score")
print melted

   Year  Country  Score
0  1990  Albania    1.0
1  1991  Albania    1.2
2  1992  Albania    2.6
3  1990  Algeria    2.0
4  1991  Algeria    2.3
5  1992  Algeria    3.3
6  1990   Andora    1.5
7  1991   Andora    6.9

8  1992   Andora    5.3
我搞乱了你的df,你的案子也一样。
更多关于熔化的信息-->

到目前为止您尝试了什么?到目前为止您尝试了什么?