python更改行的列
我只看到过与我在这里寻找的相反的帖子。使用jupyter笔记本/python,我从csv文件导入了第一个块,我想要第二个块:python更改行的列,python,dataframe,interpolation,Python,Dataframe,Interpolation,我只看到过与我在这里寻找的相反的帖子。使用jupyter笔记本/python,我从csv文件导入了第一个块,我想要第二个块: Country | 1990 | 1991 | 1992 | ---------------------------------- | Albania | 1.0 | 1.2 | 2.6 | | Algeria | 2.0 | 2.3 | 3.3 | | Andora | 1.5 | 6.9 | 5.3 | Country
Country | 1990 | 1991 | 1992 |
----------------------------------
| Albania | 1.0 | 1.2 | 2.6 |
| Algeria | 2.0 | 2.3 | 3.3 |
| Andora | 1.5 | 6.9 | 5.3 |
Country | Year | Value |
------------------------------
| Albania | 1990 | 1.0 |
| Albania | 1991 | 1.2 |
| Albania | 1992 | 2.6 |
| Algeria | 1990 | 2.0 |
| Algeria | 1990 | 2.3 |
| Algeria | 1990 | 3.3 |
etc.
我是python新手,不确定是否需要使用pandas、numpy以及哪些函数(pivot_table、re index、interpolate)。谢谢试试这个:
import pandas as pd
df = pd.read_csv('my-csv.csv')
new_df = df.set_index('Country').stack()
试试这个:
import pandas as pd
df = pd.read_csv('my-csv.csv')
new_df = df.set_index('Country').stack()
熊猫的融化功能就可以了强>
import pandas as pd
df = pd.DataFrame({'Year': [1990 , 1991 , 1992], 'Albania': [1.0 , 1.2 , 2.6 ],'Algeria':[2.0,2.3,3.3],"Andora":[1.5,6.9,5.3]})
print df
Albania Algeria Andora Year
0 1.0 2.0 1.5 1990
1 1.2 2.3 6.9 1991
2 2.6 3.3 5.3 1992
melted = pd.melt(df, id_vars=["Year"],
var_name="Country", value_name="Score")
print melted
Year Country Score
0 1990 Albania 1.0
1 1991 Albania 1.2
2 1992 Albania 2.6
3 1990 Algeria 2.0
4 1991 Algeria 2.3
5 1992 Algeria 3.3
6 1990 Andora 1.5
7 1991 Andora 6.9
8 1992 Andora 5.3
熔体重塑df(关于年)强>
import pandas as pd
df = pd.DataFrame({'Year': [1990 , 1991 , 1992], 'Albania': [1.0 , 1.2 , 2.6 ],'Algeria':[2.0,2.3,3.3],"Andora":[1.5,6.9,5.3]})
print df
Albania Algeria Andora Year
0 1.0 2.0 1.5 1990
1 1.2 2.3 6.9 1991
2 2.6 3.3 5.3 1992
melted = pd.melt(df, id_vars=["Year"],
var_name="Country", value_name="Score")
print melted
Year Country Score
0 1990 Albania 1.0
1 1991 Albania 1.2
2 1992 Albania 2.6
3 1990 Algeria 2.0
4 1991 Algeria 2.3
5 1992 Algeria 3.3
6 1990 Andora 1.5
7 1991 Andora 6.9
8 1992 Andora 5.3
我搞乱了你的df,你的案子也一样。
更多关于熔化的信息-->熊猫的熔化功能就可以了强>
import pandas as pd
df = pd.DataFrame({'Year': [1990 , 1991 , 1992], 'Albania': [1.0 , 1.2 , 2.6 ],'Algeria':[2.0,2.3,3.3],"Andora":[1.5,6.9,5.3]})
print df
Albania Algeria Andora Year
0 1.0 2.0 1.5 1990
1 1.2 2.3 6.9 1991
2 2.6 3.3 5.3 1992
melted = pd.melt(df, id_vars=["Year"],
var_name="Country", value_name="Score")
print melted
Year Country Score
0 1990 Albania 1.0
1 1991 Albania 1.2
2 1992 Albania 2.6
3 1990 Algeria 2.0
4 1991 Algeria 2.3
5 1992 Algeria 3.3
6 1990 Andora 1.5
7 1991 Andora 6.9
8 1992 Andora 5.3
熔体重塑df(关于年)强>
import pandas as pd
df = pd.DataFrame({'Year': [1990 , 1991 , 1992], 'Albania': [1.0 , 1.2 , 2.6 ],'Algeria':[2.0,2.3,3.3],"Andora":[1.5,6.9,5.3]})
print df
Albania Algeria Andora Year
0 1.0 2.0 1.5 1990
1 1.2 2.3 6.9 1991
2 2.6 3.3 5.3 1992
melted = pd.melt(df, id_vars=["Year"],
var_name="Country", value_name="Score")
print melted
Year Country Score
0 1990 Albania 1.0
1 1991 Albania 1.2
2 1992 Albania 2.6
3 1990 Algeria 2.0
4 1991 Algeria 2.3
5 1992 Algeria 3.3
6 1990 Andora 1.5
7 1991 Andora 6.9
8 1992 Andora 5.3
我搞乱了你的df,你的案子也一样。
更多关于熔化的信息-->到目前为止您尝试了什么?到目前为止您尝试了什么?