Python 如何从字典中删除键和值浮动

如何删除所有小于5的键和值？ 现在我得到了错误“RuntimeError:dictionary在迭代过程中更改了大小”

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有什么方法可以使它更有效吗？

在迭代dict时不能对其进行变异

您可以迭代密钥的副本：

import csv

price = []
score = []
numPrice = []
numScore = []
with open(r'C:\Users\Testing\Desktop\Test.csv') as f:
    reader = csv.DictReader(f)
    for row in reader:
        price.append(row['price'])
        score.append(row['helpfulness_score'])
    for item in price:
        numPrice.append(float(item))
    for item in score:
        numScore.append(float(item))
finalDict = dict(zip(numScore,numPrice))                

for k in finalDict:
    if k > 5:
        finalDict.pop(k)

或者使用dict理解，而使用筛选出大于5的键的筛选器：

for k in list(finalDict):
    if k > 5:
        finalDict.pop(k)

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finalDict={k:v代表k，v在zip（numcore，numPrice）中，如果k您可以尝试此操作，而不是在将项目存储到字典中之前弹出项目

finalDict = {k: v for k, v in zip(numScore, numPrice) if k <= 5}

在任何情况下，除非您需要将所有
{key:value}
对存储在
finalDict
中进行某些处理，否则我建议只使用第一种方法

看见
import csv

finalDict = {}
with open(r'C:\Users\Testing\Desktop\Test.csv') as f:
    reader = csv.DictReader(f)
    for row in reader:
        price = float(row['price']) # converting string to float
        score = float(row['helpfulness_score']) # converting string to float
        if score <= 5: # checking if the score is less than or equal to five
            finalDict[score] = price # stores the key, value pair

popList = [] # list to store the keys to pop
for k in finalDict:
    if k > 5:
        popList.append(k) # adding keys which will be popped later
for key in popList:
    finalDict.pop(key) # popping each key in the popList