Python 必须指定连接条件，以获取此错误。

我正在尝试联接两个表以查看其内容

Users.select().join(User_profiles).where(Users.users_id == User_profiles.users_id)

我的用户型号：

class Users(Model):
    users_id = PrimaryKeyField()
    username = CharField()
    password = CharField()
    mobile_number = CharField()
    created_at = DateTimeField()
    updated_at = DateTimeField()

    class Meta:
        database = db_connection()

class User_profiles(Model):
    users_id = IntegerField()
    user_profiles_id = PrimaryKeyField()
    profile_name =  CharField()
    address = CharField()
    created_at = DateTimeField()
    updated_at = DateTimeField()    

    class Meta:
        database = db_connection()

我的用户配置文件模型：

class Users(Model):
    users_id = PrimaryKeyField()
    username = CharField()
    password = CharField()
    mobile_number = CharField()
    created_at = DateTimeField()
    updated_at = DateTimeField()

    class Meta:
        database = db_connection()

class User_profiles(Model):
    users_id = IntegerField()
    user_profiles_id = PrimaryKeyField()
    profile_name =  CharField()
    address = CharField()
    created_at = DateTimeField()
    updated_at = DateTimeField()    

    class Meta:
        database = db_connection()

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我已将“用户模型”中的“用户id”指定为“用户配置文件模型”的外键。如何以正确的方式指定连接条件？我读过peewee文档，做过谷歌搜索，但没有任何帮助。有人能帮我写代码吗？

我认为

用户配置文件\u id

应该写成

用户配置文件\u id=ForeignKeyField（用户）