Python 从csv文件中读取值

我在csv文件中有值映射\u geo\u location，如

（123.456789.1234）

，如何在破折号中获取值，以将其添加为python中属性

lan

和

lat

geo-disposted破折号的值？

list.txt：

(123.456,789.1234)
(763.426,659.9834)
(873.566,789.6734)
(773.766,239.234)
(343.776,889.1344)
(873.766,679.1344)

然后：

logFile = "list.txt"
with open(logFile) as f:
    content = f.readlines()

# you may also want to remove empty lines
content = [l.strip() for l in content if l.strip()]

lat = []
long = []

for line in content:
    lat.append(line.rpartition(',')[2].strip(")"))
    long.append(line.rpartition(',')[0].strip("("))


print("Latitude List: {}".format(lat))
print("Longitude List: {}".format(long))

输出：

Latitude List: ['789.1234', '659.9834', '789.6734', '239.234', '889.1344', '679.1344']
Longitude List: ['123.456', '763.426', '873.566', '773.766', '343.776', '873.766']

---

我想用它来显示基于值（123.456789.1234）的地图位置，所以我想把它设为lan=123.456，lat=789.1234看看下面的答案是否有用？