Python 如何以树顺序构建StringVar结构
我想建立一个StringVar的树状结构。下图描述了(希望如此)我想要实现的目标Python 如何以树顺序构建StringVar结构,python,tkinter,tree,Python,Tkinter,Tree,我想建立一个StringVar的树状结构。下图描述了(希望如此)我想要实现的目标 A / \ / \ B C / \ / \ D E B中的任何变化都
A
/ \
/ \
B C
/ \
/ \
D E
B中的任何变化都应该触发他下面的其他StringVar的变化(D和E),但是,它不应该触发a上的变化
可以这样做吗?我为这种树状结构编写了一个类:
from tkinter import Tk, StringVar
class StringVarTree:
""" Tree of StringVars """
def __init__(self, node, left=None, right=None):
"""
node: StringVar
left: StringVarTree or None
right: StringVarTree or None
"""
self.node = node
self.left = left
self.right = right
def __repr__(self):
return "%s [%s %s]" % (self.node.get(), self.left, self.right)
def set(self, string):
# modify the node
self.node.set(string)
# propagate the modification to all branches below the node
if self.left:
self.left.set(string)
if self.right:
self.right.set(string)
if __name__ == '__main__':
root = Tk()
A = StringVar(root, "A")
B = StringVar(root, "B")
C = StringVar(root, "C")
D = StringVar(root, "D")
E = StringVar(root, "E")
# tree of StringVars
tree = StringVarTree(A, StringVarTree(B, StringVarTree(D), StringVarTree(E)), StringVarTree(C))
# thanks to the __repr__ method, we can see the tree
print(tree)
# now let's modify the B branch
tree.left.set("b")
print(tree)
你想用这个想法解决什么问题?当你说“触发变化”时,变化的本质是什么?如果B设置为“Hello”,您希望D和E设置为什么?