Python 仅将表迁移到Django中2个数据库中的1个

Python 仅将表迁移到Django中2个数据库中的1个,python,django,Python,Django,我试图在1个数据库中有选择地创建表,但在另一个数据库中没有 在我的示例中,我只想为应用程序创建表:transforms数据库中的tlocation和tcategory。但是,Django正在transforms数据库中创建所有表 以下是DB路由器配置: TRANSFORM_APPS = ('tcategory', 'tlocation') class TransformRouter(object): """ A router to control all database o

我试图在1个数据库中有选择地创建表,但在另一个数据库中没有

在我的示例中,我只想为应用程序创建表:
transforms
数据库中的
tlocation
tcategory
。但是,Django正在
transforms
数据库中创建所有表

以下是DB路由器配置:

TRANSFORM_APPS = ('tcategory', 'tlocation')


class TransformRouter(object):
    """
    A router to control all database operations on models in the
    "utils_transform" application.
    """
    def db_for_read(self, model, **hints):
        """
        Attempts to read 'transforms' models go to 'transforms' database.
        """
        if model._meta.app_label in TRANSFORM_APPS:
            return 'transforms'
        return None

    def db_for_write(self, model, **hints):
        """
        Attempts to write 'transforms' models go to 'transforms' database.
        """
        if model._meta.app_label in TRANSFORM_APPS:
            return 'transforms'
        return None

    def allow_relation(self, obj1, obj2, **hints):
        """
        Allow relations if a model in the 'tlocation' app is involved.
        """
        if obj1._meta.app_label in TRANSFORM_APPS or \
           obj2._meta.app_label in TRANSFORM_APPS:
           return True
        return None

    def allow_migrate(self, db, app_label, model=None, **hints):
        """
        Make sure the 'tlocation' app only appears in the 'transforms'
        database.
        """
        if app_label in TRANSFORM_APPS:
            return db == 'transforms'
        return None


class DefaultRouter(object):
    """
    Catch-all Router for all other DB transactions that aren't in the 
    ``utils_transform`` app.
    """

    def db_for_read(self, model, **hints):
        return 'default'

    def db_for_write(self, model, **hints):
        return 'default'

    def allow_relation(self, obj1, obj2, **hints):
        if obj1._state.db == obj2._state.db:
           return True
        return None

    def allow_migrate(self, db, app_label, model=None, **hints):
        return None
我用于运行迁移的命令是:

./manage.py migrate --database=transforms
当我一次只迁移一个应用程序时,如下所示,这是可行的。但是如果在
migrate
命令中没有应用程序过滤器,我就无法运行。例如:

./manage.py migrate tlocation --database=transforms
./manage.py migrate tcategory --database=transforms

对于不想创建表的模型,您是否尝试过
managed=False

class MyModel(models.Model):
    ...
    class Meta:
        managed = False

您确认它实际上正在创建表吗?因为无论哪种情况下,
migrate
的输出看起来都是一样的,所以它“只会在返回
False
的模型上默默地不执行任何操作”。@KevinChristopherHenry,yes,它正在创造tables@AaronLelevier数据库路由器设置中路由器的顺序是什么?这也无法区分数据库。它不会在任何数据库中创建表。