Python 打印内容以便对齐时遇到问题
我正试图打印出我的结果列表,但我希望它们是一致的。它们目前看起来像:Python 打印内容以便对齐时遇到问题,python,python-3.x,Python,Python 3.x,我正试图打印出我的结果列表,但我希望它们是一致的。它们目前看起来像: table word: frequency: i 9 my 2 to 2 test 2 it 2 hate 1 stupid 1
table
word: frequency:
i 9
my 2
to 2
test 2
it 2
hate 1
stupid 1
accounting 1
class 1
because 1
its 1
from 1
six 1
seven 1
pm 1
how 1
is 1
this 1
helping 1
becuase 1
im 1
going 1
do 1
a 1
little 1
on 1
freind 1
ii 1
我希望频率彼此对齐,这样它们就不会以这种奇怪的之字形运动。我试着在格式中添加一些东西,但没有成功。这就是我的代码的样子:
import string
from collections import OrderedDict
f=open('mariah.txt','r')
a=f.read() # read the text file like it would normal look ie no \n or anything
# print(a)
c=a.lower() # convert everything in the textfile to lowercase
# print(c)
y=c.translate(str.maketrans('','',string.punctuation)) # get rid of any punctuation
# print(y)
words_in_novel=y.split() # splitting every word apart. the default for split is on white-space characters. Why when i split like " " for the spacing is it then giving me \n?
#print(words_in_novel)
count={}
for word in words_in_novel:
#print(word)
if word in count: # if the word from the word_in_novel is already in count then add a one to that counter
count[word]+=1
else:
count[word]=1 # if the word is the first time in count set it to 1
print(count)
print("\n\n\n\n\n\n\n")
# this orderes the dictionary where its sorts them by the second term wehre t[1] refers to the term after the colon
# reverse so we are sorting from greatest to least values
g=(sorted(count.items(), key=lambda t: t[1], reverse=True))
# g=OrderedDict(sorted(count.items(), key=lambda t: t[1]))
print(g)
print("\n\n\n\n\n\n\n")
print("{:^20}".format("table"))
print("{}{:>20}".format("word:","frequency:"))
for i in g:
# z=g[i]
# print(i)
# a=len(i[0])
# print(a)
# c=50+a
# print(c)
print("{}{:>20}".format(i[0],i[1]))
有人知道如何让他们走直线吗 您需要调整第一列的宽度/对齐,而不是第二列。
正确的方法:
...
print("{:<20}{}".format("word:","frequency:"))
for i in g:
print("{:<20}{}".format(i[0],i[1]))
您需要调整第一列的宽度/对齐,而不是第二列。
正确的方法:
...
print("{:<20}{}".format("word:","frequency:"))
for i in g:
print("{:<20}{}".format(i[0],i[1]))
好的,对于代码部分:
for i in g:
r = " "*25
#print("{}{:>20}".format(i[0],i[1]))
r[:len(i[0])] = i[0]
r = r[:22]+str(i[1])
print(r)
它应该可以工作好的,对于代码部分:
for i in g:
r = " "*25
#print("{}{:>20}".format(i[0],i[1]))
r[:len(i[0])] = i[0]
r = r[:22]+str(i[1])
print(r)
如果您发现频率大于一个位数,您可以尝试以下方法:
max_len = max(len(i[0]) for i in g)
format_str = "{{:<{}}}{{:>{}}}".format(max_len, 20 - max_len)
for i in g:
print(format_str.format(i[0], i[1]))
max\u len=max(len(i[0])表示i in g)
format_str=“{{:{}}}”。format(max_len,20-max_len)
对于i in g:
打印(格式\u str.format(i[0],i[1]))
如果您发现频率大于一位数,您可以尝试以下方法:
max_len = max(len(i[0]) for i in g)
format_str = "{{:<{}}}{{:>{}}}".format(max_len, 20 - max_len)
for i in g:
print(format_str.format(i[0], i[1]))
max\u len=max(len(i[0])表示i in g)
format_str=“{{:{}}}”。format(max_len,20-max_len)
对于i in g:
打印(格式\u str.format(i[0],i[1]))
将单词也对齐
print("{:<10}{:>10}".format(i[0],i[1]))
print(“{:10}”。格式(i[0],i[1]))
将单词也对齐
print("{:<10}{:>10}".format(i[0],i[1]))
print(“{:10}”。格式(i[0],i[1]))
您需要单词列具有固定宽度您需要单词列具有固定宽度哇,谢谢!为什么在第一个元素上这样做会起作用?@Brit,不客气。specificator{:它是从行的开头而不是单词的结尾扩展的吗?哇,谢谢!当你在第一个元素上这样做时,它为什么起作用?@Brit,不客气。specificator{:它是从行的开头而不是单词的结尾扩展的吗?