在python中为字符串中的单词赋值

嗨，我在python中有一个压缩任务来开发代码，如果输入是

“你好，是我，你好，你能听到我吗，你好，你在听吗”

那么输出应该是

1,2,3,1,4,5,6,3,1,7,5,8

基本上，每个单词都有一个数值，如果单词重复，那么这个单词也会重复。

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此编码是用python编写的，请帮助我谢谢

一种简单的方法是使用dict，当您发现一个新词时，使用递增变量添加一个键/值对，当您在刚刚打印dict中的值之前看到该词时：

s = 'hello its me, hello can you hear me, hello are you listening'


def cyc(s):
    # set i to 1 
    i = 1
    # split into words on whitespace
    it = s.split()
    # create first key/value pair 
    seen = {it[0]: i}
    # yield 1 for first word
    yield i
    # for all var the first word
    for word in it[1:]:
        # if we have seen this word already, use it's value from our dict
        if word in seen:
            yield seen[word]
        # else first time seeing it so increment count
        # and create new k/v pairing
        else:
            i += 1
            yield i
            seen[word] = i


print(list(cyc(s)))

输出：

[1, 2, 3, 1, 4, 5, 6, 3, 1, 7, 5, 8]

您还可以通过使用

iter

并调用

next

弹出第一个单词来避免切片，如果您想使

foo==foo我们需要从字符串中删除任何标点符号，这可以通过str.rstrip完成：

一种简单的方法是使用dict，当您发现一个新词时，使用递增变量添加一个键/值对，当您在刚刚打印dict中的值之前看到该词时：

s = 'hello its me, hello can you hear me, hello are you listening'


def cyc(s):
    # set i to 1 
    i = 1
    # split into words on whitespace
    it = s.split()
    # create first key/value pair 
    seen = {it[0]: i}
    # yield 1 for first word
    yield i
    # for all var the first word
    for word in it[1:]:
        # if we have seen this word already, use it's value from our dict
        if word in seen:
            yield seen[word]
        # else first time seeing it so increment count
        # and create new k/v pairing
        else:
            i += 1
            yield i
            seen[word] = i


print(list(cyc(s)))

输出：

[1, 2, 3, 1, 4, 5, 6, 3, 1, 7, 5, 8]

您还可以通过使用
iter
并调用
next
弹出第一个单词来避免切片，如果您想使
foo==foo我们需要从字符串中删除任何标点符号，这可以通过str.rstrip完成：

如何使用item:index映射构建一个
dict
：

>>> s
'hello its me, hello can you hear me, hello are you listening'
>>> 
>>> l = s.split()
>>> d = {}
>>> i = 1
>>> for x in l:
        if x not in d:
            d[x]=i
            i += 1


>>> d
{'its': 2, 'listening': 8, 'hear': 6, 'hello': 1, 'are': 7, 'you': 5, 'me,': 3, 'can': 4}
>>> for x in l:
        print(x, d[x])


hello 1
its 2
me, 3
hello 1
can 4
you 5
hear 6
me, 3
hello 1
are 7
you 5
listening 8
>>> 

如果您不希望分割列表中有任何标点符号，则可以执行以下操作：

>>> import re
>>> l = re.split(r'(?:,|\s)\s*', s)
>>> l
['hello', 'its', 'me', 'hello', 'can', 'you', 'hear', 'me', 'hello', 'are', 'you', 'listening']

如何使用item:index映射构建一个
dict
：

>>> s
'hello its me, hello can you hear me, hello are you listening'
>>> 
>>> l = s.split()
>>> d = {}
>>> i = 1
>>> for x in l:
        if x not in d:
            d[x]=i
            i += 1


>>> d
{'its': 2, 'listening': 8, 'hear': 6, 'hello': 1, 'are': 7, 'you': 5, 'me,': 3, 'can': 4}
>>> for x in l:
        print(x, d[x])


hello 1
its 2
me, 3
hello 1
can 4
you 5
hear 6
me, 3
hello 1
are 7
you 5
listening 8
>>> 

如果您不希望分割列表中有任何标点符号，则可以执行以下操作：

>>> import re
>>> l = re.split(r'(?:,|\s)\s*', s)
>>> l
['hello', 'its', 'me', 'hello', 'can', 'you', 'hear', 'me', 'hello', 'are', 'you', 'listening']

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