Python 如果列表编号为偶数或奇数，则打印

我想让我的代码打印1,2,3,4,5,6，如果每个代码是偶数或奇数，则具体显示，但它只显示数字，不显示备注，

if/else需要在for循环中：

listofNumbers = [1, 2, 3, 4, 5, 6]
for number in listofNumbers:
    print  (number),
if (number % 2 ==0):
    print (" is even")
else :
    print(" is odd")

print("All done.")

---

您可以删除第一条打印语句-在L3上。它现在只是在循环中通过阵列进行打印。删除第3行或注释掉它，在print语句中将number转换为str类型，它将按照您的意愿执行

listofNumbers = [1, 2, 3, 4, 5, 6]
for number in listofNumbers:
    print(number, end="" )
    if (number % 2 ==0):
        print(" is even")
    else :
        print(" is odd")
print("All done.")

---

修正你的缩进。您的

if

必须在

for

循环中。已实施改进！

listofNumbers = [1, 2, 3, 4, 5, 6]
for number in listofNumbers:
    if (number % 2 == 0):
        print (str(number) + " is even")
    else:
        print(str(number) + " is odd")

print("All done.")