Python 如何通过检查行x+；1-行x大于某个值（熊猫）

我有一张这样的桌子：

Dates,               Minutes
1/24/2020 2:58:04 PM, 0
1/24/2020 3:13:04 PM, 0
1/27/2020 10:04:09 AM, 3
1/27/2020 10:19:09 AM, 0
1/27/2020 10:34:09 AM, 0
1/27/2020 10:49:10 AM, 1
1/27/2020 11:04:09 AM, 0
1/27/2020 11:19:09 AM, 1
1/27/2020 11:34:09 AM, 1
1/27/2020 11:49:09 AM, 0
1/27/2020 12:04:09 PM, 13
1/27/2020 12:19:09 PM, 0
1/27/2020 12:34:09 PM, 0
1/27/2020 12:49:09 PM, 0
1/27/2020 1:04:09 PM, 11
1/27/2020 1:19:09 PM, 26
1/27/2020 1:34:09 PM, 41
1/27/2020 1:49:09 PM, 0
1/27/2020 2:04:09 PM, 0
1/27/2020 2:19:09 PM, 12
1/27/2020 2:34:09 PM, 0

我希望检查当前行与前一行之间的差异是否大于或等于15，然后将该值更改为15。 因此，新表将如下所示：

Dates,               Minutes
1/24/2020 2:58:04 PM, 0
1/24/2020 3:13:04 PM, 0
1/27/2020 10:04:09 AM, 3
1/27/2020 10:19:09 AM, 0
1/27/2020 10:34:09 AM, 0
1/27/2020 10:49:10 AM, 1
1/27/2020 11:04:09 AM, 0
1/27/2020 11:19:09 AM, 1
1/27/2020 11:34:09 AM, 1
1/27/2020 11:49:09 AM, 0
1/27/2020 12:04:09 PM, 13
1/27/2020 12:19:09 PM, 0
1/27/2020 12:34:09 PM, 0
1/27/2020 12:49:09 PM, 0
1/27/2020 1:04:09 PM, 11
1/27/2020 1:19:09 PM, 15*
1/27/2020 1:34:09 PM, 15*
1/27/2020 1:49:09 PM, 0
1/27/2020 2:04:09 PM, 0
1/27/2020 2:19:09 PM, 12
1/27/2020 2:34:09 PM, 0

*=值已更改

df.Minutes = df.Minutes.mask(df.Minutes.diff().ge(15), 15)

让我们做吧

df.Minutes = df.Minutes.mask(df.Minutes.diff().ge(15), 15)

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另一种方法是使用

.loc

和

shift

df.loc[(df['Minutes'] - df['Minutes'].shift(1)).ge(15),'Minutes'] = 15

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另一种方法是使用

.loc

和

shift

df.loc[(df['Minutes'] - df['Minutes'].shift(1)).ge(15),'Minutes'] = 15

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