Python 有没有一种方法可以绘制一侧带有圆弧的matplotlib面片矩形？

我需要画一个多边形，它有4条边，右边是圆弧。与此类似：

我曾尝试将matplotlib提供的代码用于bezier曲线，但没有成功。任何帮助都将不胜感激：）

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我不知道这是否是绘制路径对象的正确方法-您最好等待有此方法经验的人。但在此之前，您可以这样做：

from matplotlib.path import Path
import matplotlib.patches as patches


verts = [
   (0, 0),    # P0
   (0, 1),    # P1
   (1, 1),    # P2
   (0.4, 1),  #these are the vertices for the 
   (0.2, 0),  #Bezier curve
   (0.5, 0),  # P3
   (0, 0)     #and back to P0
]

codes = [
    Path.MOVETO,  # P0
    Path.LINETO,  #line to P1
    Path.LINETO,  #line to P2
    Path.CURVE4,  #control point one for the Bezier curve
    Path.CURVE4,  #control point two
    Path.CURVE4,  #end point for the Bezier curve
    Path.LINETO   #and back to P0
 ]

path = Path(verts, codes)

fig, ax = plt.subplots()
patch = patches.PathPatch(path, facecolor='none', lw=2)
ax.add_patch(patch)

#you can add the hull figure for the Bezier curve
#xs, ys = zip(*verts)
#ax.plot(xs, ys, "x--", lw=2, color='black', ms=10) 

ax.set_xlim(-0.1, 1.1)
ax.set_ylim(-0.1, 1.1)
plt.show()

样本输出：

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表示对于贝塞尔曲线，除了当前位置之外，还需要两个控制点和一个端点。因此，您的四点方法可能还不够。

非常感谢！这正是我需要的

from matplotlib.path import Path
import matplotlib.patches as patches


verts = [
   (0, 0),    # P0
   (0, 1),    # P1
   (1, 1),    # P2
   (0.4, 1),  #these are the vertices for the 
   (0.2, 0),  #Bezier curve
   (0.5, 0),  # P3
   (0, 0)     #and back to P0
]

codes = [
    Path.MOVETO,  # P0
    Path.LINETO,  #line to P1
    Path.LINETO,  #line to P2
    Path.CURVE4,  #control point one for the Bezier curve
    Path.CURVE4,  #control point two
    Path.CURVE4,  #end point for the Bezier curve
    Path.LINETO   #and back to P0
 ]

path = Path(verts, codes)

fig, ax = plt.subplots()
patch = patches.PathPatch(path, facecolor='none', lw=2)
ax.add_patch(patch)

#you can add the hull figure for the Bezier curve
#xs, ys = zip(*verts)
#ax.plot(xs, ys, "x--", lw=2, color='black', ms=10) 

ax.set_xlim(-0.1, 1.1)
ax.set_ylim(-0.1, 1.1)
plt.show()