Python 我们如何定义接受参数的@list\u路由

在我的应用程序中，我有一个

ModelViewSet

，其中有一个

@list\u route（）

定义的函数，用于获取列表，但具有不同的序列化程序

class AnimalViewSet(viewsets.ModelViewSet):
    """
    This viewset automatically provides `list`, `create`, `retrieve`,
    `update` and `destroy` actions.
    """
    queryset = Animal.objects.all()
    serializer_class = AnimalSerializer // Default modelviewset serializer

    lookup_field = 'this_id'

    @list_route()
    def listview(self, request):
        query_set = Animal.objects.all()
        serializer = AnimalListingSerializer(query_set, many=True) // Serializer with different field included.
         return Response(serializer.data)

带有此

/api/animal/

端点的默认

AnimalViewSet

根据

AnimalSerializer

定义生成此序列化数据结果

{
    "this_id": "1001",
    "name": "Animal Testing 1",
    "species_type": "Cow",
    "breed": "Brahman",
    ...
    "herd": 1
},
{
    "this_id": "1004",
    "name": "Animal Testing 2",
    "species_type": "Cow",
    "breed": "Holstien",
    ....
    "herd": 1
},
{
    "this_id": "1020",
    "name": "Animal Testing 20",
    "species_type": "Cow",
    "breed": "Brahman",
    ....
    "herd": 4
},

另一个是名为

listview

的

@list\u route（）

定义函数，它可能有一个端点

/api/animal/listview/

，该端点产生

AnimalListingSerializer

结构中定义的结果

{
    "this_id": "1001",
    "name": "Animal Testing 1",
    "species_type": "Cow",
    "breed": "Brahman",
    ....
    "herd": {
        "id": 1,
        "name": "High Production",
        "description": null
    }
},
{
    "this_id": "1004",
    "name": "Animal Testing 2",
    "species_type": "Cow",
    "breed": "Holstien",
    ....
    "herd": {
        "id": 1,
        "name": "High Production",
        "description": null
    }
},
{
    "this_id": "1020",
    "name": "Animal Testing 20",
    "species_type": "Cow",
    "breed": "Brahman",
    ....
    "herd": {
        "id": 4,
        "name": "Bad Production",
        "description": "Bad Production"
    }
}

现在我要做的是定义另一个

@list\u route（）

函数，它接受一个参数并使用

AnimalListingSerializer

来过滤模型对象的

查询集

结果。为像我们这样的初学者提供帮助的工作

@list_route()
def customList(self, request, args1, args2):
        query_set = Animal.objects.filter(species_type=args1, breed=args2)
        serializer = AnimalListingSerializer(query_set, many=True)
         return Response(serializer.data)

让我们假设

args1=“Cow”

和

args2=“Brahman”

。我期待着这个结果

{
    "this_id": "1001",
    "name": "Animal Testing 1",
    "species_type": "Cow",
    "breed": "Brahman",
    ....
    "herd": {
        "id": 1,
        "name": "High Production",
        "description": null
    }
},
{
    "this_id": "1020",
    "name": "Animal Testing 20",
    "species_type": "Cow",
    "breed": "Brahman",
    ....
    "herd": {
        "id": 4,
        "name": "Bad Production",
        "description": "Bad Production"
    }
},

但我知道我的语法是错误的，但这就是我要说的。 请帮忙

---

view函数中的参数是为URL引用保留的。也就是说，路由/5将被传递给一个以pk为参数的视图函数

def get(self, request, pk):
    # get animal with pk
    return animal with pk

您可以通过查询参数将参数传递到url

/anives/listview/？speceis_type=cow&breed=braham

然后使用请求对象在视图中访问它

request.query_-params['speceis\u-type']

和

request.query_-params['braham']

或者您可以使用有文档记录的django rest过滤器中间件