Python失败的IF语句/更改变量

我有个问题。如能迅速回复，将不胜感激！如果我的函数没有为我正确更改全局变量，那么我的程序将失败。比如说，他们应该能够去南方拿钥匙。有了那把钥匙，他们可以向东走，打开一个锁着的抽屉。除了他们没有通过if检查，无法打开抽屉

提前谢谢！有问题的代码块应该在下面

def south():
    print ("You can see a key just lying there on the table! What luck!")
    choice = raw_input("You better TAKE that!")
    if choice == 'TAKE' :
        print "You took the key!"
        return Key1 == 1, moverooms()
    else:
        print "You didn't take the key to freedom!?"
        south()


def east():
    print("You can see a drawer here! Wonder what is inside?")
    choice = raw_input("You can MOVEROOMS, or try to USE the drawer and TAKE what's inside...\n ")
    if choice == 'USE' :
        print "You try to open the drawer... \n"
        if Key1 == 1 :
            print "You use the key to open the drawer and find a flashlight inside! Better TAKE it!"
            Drawer == 1
            east()

    else:
        print ("It's locked! Better find a key...\n")
        east()

---

您确实不想使用全局变量，但如果必须使用，您的问题似乎是您没有在

TAKE

条件中分配

Key1=1

，而是根据它是否已经具有该值（

Key1==1

）返回

True

或

False

）。请注意，您需要在

返回之前设置它

请注意，如果要执行此操作（不执行），则需要在
south（）函数的顶部断言
global Key

要避免全局变量，请从
south
返回
Key1
的值，并将其传递给
east
：

def south():
    print ("You can see a key just lying there on the table! What luck!")
    choice = raw_input("You better TAKE that!")
    if choice == 'TAKE' :
        print "You took the key!"
        Key1 = 1
    else:
        print "You didn't take the key to freedom!?"
        Key1 = 0
    return Key1

def east(Key1):
    print("You can see a drawer here! Wonder what is inside?")
    choice = raw_input("You can MOVEROOMS, or try to USE the drawer and TAKE what's inside...\n ")
    if choice == 'USE' :
        print "You try to open the drawer... \n"
        if Key1 == 1 :
            print "You use the key to open the drawer and find a flashlight inside! Better TAKE it!"
            Drawer = 1
            return Drawer
    else:
        print ("It's locked! Better find a key...\n")
        Drawer = 0
    return Drawer

不过，您必须自己处理对
南部
和
东部
的调用逻辑。
这可能有些过分，但理想情况下，您将按照以下思路进行操作：

class Character(object):
    """
    This class represents the player.
    It keeps track of found items, opened drawers, etc...
    """

    def __init__(self):
        # game start: Key not found, drawer not opened.
        self.has_key= False
        self.has_opened_drawer= False

    def go_south(self):
        print "You can see a key just lying there on the table! What luck!"
        choice = raw_input("You better TAKE that!\n")
        if choice == 'TAKE' :
            print "You took the key!"
            self.has_key= True
        else:
            print "You didn't take the key to freedom!?"

    def go_east(self):
        print "You can see a drawer here! Wonder what is inside?"
        choice = raw_input("You can MOVEROOMS, or try to USE the drawer and TAKE what's inside...\n")
        if choice == 'USE':
            print "You try to open the drawer... \n"
            if self.has_key:
                print "You use the key to open the drawer and find a flashlight inside! Better TAKE it!"
                self.has_opened_drawer= True
        else:
            print "It's locked! Better find a key...\n"

    def input_loop(self):
        while True:
            choice= raw_input('Do you want to go SOUTH or EAST?\n')
            if choice=='SOUTH':
                self.go_south()
            elif choice=='EAST':
                self.go_east()

player= Character() # create a Character
player.input_loop() # and let the user control it

不使用全局变量，而是创建一个
字符
来存储所有必要的数据，例如是否找到了钥匙，抽屉是否已打开。这样你就不会因为变量而使全局范围混乱。
嘿，我只是把它改成==1，因为它给了我一个语法错误。我是个新手；如何使用非“全局”且在程序开始时初始化的变量？返回键1==1，moverooms（）
的意义是什么？我几乎可以向你们保证，这行代码并没有做你们认为它做的事情——我对python和编程都是新手；在最终放弃并发布到堆栈之前，我多次尝试修复这一问题，其中一次就是把这一行放在这里的。您没有任何全局变量。你认为哪个变量是全局变量？除了没有任何全局变量外，你没有设置任何变量。（除了
选项
）