Python 属性错误：'；int'；对象没有属性'；钥匙'；

下面是我正在迭代的数据框架中的列

下面是我写的代码

def count_entries(df,col_name):
    """ Return a dictionary with counts of occurrences as value for each key"""
    cols_count = {}
    col = df[col_name]
    for entry in col:
        if entry in cols_count.keys():
            cols_count[entry] += 1
        else:
            cols_count = 1
    return cols_count
result = count_entries(data, 'gun_stolen')
print (result)

---

您可以通过以下方式简化解决方案：

或使用：

---

您可以通过以下方式简化解决方案：

或使用：

---

cols\u count=1

？

cols\u count=1

？

def count_entries(df,col_name):
    """ Return a dictionary with counts of occurrences as value for each key"""
    cols_count = {}
    col = df[col_name]
    for entry in col:
        if entry in cols_count.keys():
            cols_count[entry] += 1
        else:
            cols_count = 1
    return cols_count
result = count_entries(data, 'gun_stolen')
print (result)

df = pd.DataFrame({
        'A':list('abcdef'),
         'F':list('aaabbc')
})

print (df)
   A  F
0  a  a
1  b  a
2  c  a
3  d  b
4  e  b
5  f  c

def count_entries(df,col_name):
    """ Return a dictionary with counts of occurrences as value for each key"""
    return df[col_name].value_counts().to_dict()

from collections import Counter

def count_entries(df,col_name):
    """ Return a dictionary with counts of occurrences as value for each key"""
    return dict(Counter(df[col_name]))

result = count_entries(df, 'F')
print (result)
{'a': 3, 'b': 2, 'c': 1}

def count_entries(df,col_name):
    """ Return a dictionary with counts of occurrences as value for each key"""
    cols_count = {}
    col = df[col_name]
    for entry in col:
        if entry in cols_count.keys():
            cols_count[entry] += 1
        else:
            # you forgot the [entry] in else statement.
            cols_count[entry] = 1
    return cols_count
result = count_entries(data, 'gun_stolen')
print (result)