获取Python中的下一对字典

我有一个字典列表，其中包含我想提取的值。以下是这份名单的规模

 input =  [
  [
    {
      "field": "@timestamp",
      "value": "2019-05-07 13: 40: 31.103"
    },
    {
      "field": "B",
      "value": 22
    },
    {
      "field": "@message",
      "value": "123 aaa 456 bbb"
    }
  ],
  [
    {
      "field": "@timestamp",
      "value": "2019-05-08 13: 40: 31.103"
    },
    {
      "field": "B",
      "value": 11
    },
    {
      "field": "@message",
      "value": "123 yyy 456 zzz"
    }
  ]
  ,
  ...
]

我想迭代列表，并为每次迭代获取

@timestamp

和

@message

的值。时间戳总是每个列表的第一个元素，消息是第三个元素，但我不想依赖元素的顺序

这是我到目前为止所做的，但我不知道如何得到下一双

for list in input:
    for dict in list:
        for x, y in dict.items():
            if x == 'field' and y == '@timestamp':
                print(y)
                # Here i want to get the values of the next pair and continue to the next iteration
            elif x == 'field' and y == '@message':
                print(y)
                # Here i want to get the values of the next pair and continue to the next iteration

---

任何人都可以帮助？

使用简单的迭代

Ex:

data =  [
  [
    {
      "field": "@timestamp",
      "value": "2019-05-07 13: 40: 31.103"
    },
    {
      "field": "B",
      "value": 22
    },
    {
      "field": "@message",
      "value": "123 aaa 456 bbb"
    }
  ],
  [
    {
      "field": "@timestamp",
      "value": "2019-05-08 13: 40: 31.103"
    },
    {
      "field": "B",
      "value": 11
    },
    {
      "field": "@message",
      "value": "123 yyy 456 zzz"
    }
  ]
]

for elem in data:
    for sub_elem in elem:
        if sub_elem["field"] in ["@timestamp", "@message"]:
            print(sub_elem["value"])

2019-05-07 13: 40: 31.103
123 aaa 456 bbb
2019-05-08 13: 40: 31.103
123 yyy 456 zzz

输出：

data =  [
  [
    {
      "field": "@timestamp",
      "value": "2019-05-07 13: 40: 31.103"
    },
    {
      "field": "B",
      "value": 22
    },
    {
      "field": "@message",
      "value": "123 aaa 456 bbb"
    }
  ],
  [
    {
      "field": "@timestamp",
      "value": "2019-05-08 13: 40: 31.103"
    },
    {
      "field": "B",
      "value": 11
    },
    {
      "field": "@message",
      "value": "123 yyy 456 zzz"
    }
  ]
]

for elem in data:
    for sub_elem in elem:
        if sub_elem["field"] in ["@timestamp", "@message"]:
            print(sub_elem["value"])

2019-05-07 13: 40: 31.103
123 aaa 456 bbb
2019-05-08 13: 40: 31.103
123 yyy 456 zzz

---

可以向列表中添加枚举数，对循环中的当前索引进行计数。然后以该值提取字典

for list in input:
    for i, dict in enumerate(list):
        for x, y in dict.items():
            if x == 'field' and (y == '@timestamp' or y == '@message'):
                print(list[i])

印刷品：

{'field': '@timestamp', 'value': '2019-05-07 13: 40: 31.103'}
{'field': '@message', 'value': '123 aaa 456 bbb'}
{'field': '@timestamp', 'value': '2019-05-08 13: 40: 31.103'}
{'field': '@message', 'value': '123 yyy 456 zzz'}

---

这对于常规字典来说是个坏主意，键没有排序没有正确的“下一个”如果你坚持这样做，把你的dict变成不确定你所说的“下一对”是什么意思，你能详细说明一下吗？你应该避免将变量命名为与构建时相同的名称-ins@Faboor，下一对

“字段”：“@timestamp”

例如将是

“值”：“2019-05-07 13:40:31.103”

。我希望足够清楚。太好了！比我想象的容易多了。谢谢：）