Python 按数值对字典排序
我对音乐类型有一个Python 按数值对字典排序,python,list,dictionary,tuples,Python,List,Dictionary,Tuples,我对音乐类型有一个dict: tag_weight = {'industrial': '533621', 'indie': '1971962', 'metal': '1213678', 'heavy metal': '652471', 'japanese': '428102', 'pop': '1873806', 'new wave': '399507', 'black metal': '772132', 'rap': '513024', 'ambient': '1030414', 'alter
dict
:
tag_weight = {'industrial': '533621', 'indie': '1971962', 'metal': '1213678', 'heavy metal': '652471', 'japanese': '428102', 'pop': '1873806', 'new wave': '399507', 'black metal': '772132', 'rap': '513024', 'ambient': '1030414', 'alternative': '2059313', 'hard rock': '820796', 'electronic': '2288563', 'blues': '531045', 'folk': '882178', 'classic rock': '1123712', 'alternative rock': '1123488', '90s': '447671', 'indie rock': '850515', 'death metal': '671118', 'electronica': '614494', 'female vocalists': '1557702', 'Soundtrack': '529406', 'dance': '769039', 'funk': '399843', 'psychedelic': '458710', '80s': '751871', 'piano': '409931', 'chillout': '636088', 'post-rock': '426516', 'punk rock': '518515', 'jazz': '1117114', 'seen live': '2097509', 'instrumental': '817816', 'singer-songwriter': '810185', 'metalcore': '444383', 'hardcore': '656111', 'Hip-Hop': '814630', 'hip hop': '394989', 'Classical': '539190', 'punk': '848955', 'soul': '641095', 'british': '667559', 'thrash metal': '465163', 'Progressive metal': '407220', 'rock': '3879179', 'acoustic': '460841', 'german': '409030', 'Progressive rock': '693480', 'experimental': '1010190'}
我想按流行程度对它们进行标记,也就是说,按值排序
,从最流行到最不流行
由于dicts
本质上是无序的,因此我必须使用tuples
,我一直在尝试使用这个:
sorted_dict = sorted(tag_weight.items(), key=operator.itemgetter(0), reverse=True)
但它似乎不起作用,因为它返回:
[('thrash metal', '465163'), ('soul', '641095'), ('singer-songwriter', '810185'), ('seen live', '2097511'), ('rock', '3879179'), ('rap', '513024'), ('punk rock', '518515'), ('punk', '848955'), ('psychedelic', '458710'), ('post-rock', '426516'), ('pop', '1873806'), ('piano', '409931'), ('new wave', '399507'), ('metalcore', '444383'), ('metal', '1213678'), ('jazz', '1117114'), ('japanese', '428102'), ('instrumental', '817816'), ('industrial', '533621'), ('indie rock', '850515'), ('indie', '1971962'), ('hip hop', '394989'), ('heavy metal', '652471'), ('hardcore', '656111'), ('hard rock', '820796'), ('german', '409030'), ('funk', '399843'), ('folk', '882178'), ('female vocalists', '1557702'), ('experimental', '1010190'), ('electronica', '614494'), ('electronic', '2288563'), ('death metal', '671118'), ('dance', '769039'), ('classic rock', '1123712'), ('chillout', '636088'), ('british', '667559'), ('blues', '531045'), ('black metal', '772132'), ('ambient', '1030414'), ('alternative rock', '1123488'), ('alternative', '2059313'), ('acoustic', '460841'), ('Soundtrack', '529406'), ('Progressive rock', '693480'), ('Progressive metal', '407220'), ('Hip-Hop', '814630'), ('Classical', '539190'), ('90s', '447671'), ('80s', '751871')]
我想('rock','3879179')
应该是榜首
我做错了什么?您当前正在按键排序,而不是按值排序,并且您还希望将类型转换为整数,以避免按字典顺序排序:
使用为此目的而构建的
collections.Counter
:
import collections
# Convert values to int
tag_weight = {k: int(v) for k, v in tag_weight.items()}
count = collections.Counter(tag_weight)
# Print the top 10
print count.most_common(10)
# Print all, from most popular to least
print count.most_common()
前10名的产出:
[('rock', 3879179), ('electronic', 2288563), ('seen live', 2097509), ('alternative', 2059313), ('indie', 1971962), ('pop', 1873806), ('female vocalists', 1557702), ('metal', 1213678), ('classic rock', 1123712), ('alternative rock', 1123488)]
[('rock', 3879179), ('electronic', 2288563), ('seen live', 2097509), ('alternative', 2059313), ('indie', 1971962), ('pop', 1873806), ('female vocalists', 1557702), ('metal', 1213678), ('classic rock', 1123712), ('alternative rock', 1123488)]