Python tkinter按钮运行命令并销毁弹出窗口
我使用tkinter在Python3中工作,希望在弹出窗口中有一个按钮,运行命令并销毁弹出窗口。下面的代码在前端工作,但在命令行中出现错误,这是一个可以解决的问题吗 我得到的错误是: 回溯(最近一次呼叫最后一次):Python tkinter按钮运行命令并销毁弹出窗口,python,tkinter,Python,Tkinter,我使用tkinter在Python3中工作,希望在弹出窗口中有一个按钮,运行命令并销毁弹出窗口。下面的代码在前端工作,但在命令行中出现错误,这是一个可以解决的问题吗 我得到的错误是: 回溯(最近一次呼叫最后一次): 文件“C:Python34\lib\tkinter\uuuu intit\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu 返回self.func(*args) 文件“test.py”
文件“C:Python34\lib\tkinter\uuuu intit\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu 返回self.func(*args)
文件“test.py”,第14行,在
command=lambda:display_something()*popup.destroy())
TypeError:&:'NoneType'和'NoneType'的操作数类型不受支持
&
是“and”运算符,但用于位
,不用于布尔值
您需要布尔运算符和
但是在您的代码中,或
应该工作得更好,因为第一个函数返回的None
被视为False
,而False和anything总是False
,所以不需要执行anything
。但是False或anything
可能根据anything
给出False
或True
,因此它必须执行anything
才能得到最终结果。)
你能将错误信息添加到问题中吗?非常好,谢谢你的解释!
from tkinter import *
class MainView(Frame):
def __init__(self,master):
Frame.__init__(self,master)
self.grid()
new_popup = Button(self,text = 'Make A Popup!',
command = lambda: popup()).grid(row=0,column=0)
def popup():
popup = Toplevel()
button = Button(popup, text = 'Display something on the command line',
command = lambda: display_something() & popup.destroy())
button.pack()
def display_something():
print('popup ran the command')
def main():
root = Tk()
root.title('Eric\'s Archiver')
app = MainView(root)
root.mainloop()
if __name__ == '__main__':
main()
lambda: display_something() or popup.destroy()