python通过增加文本文件中的编号来管理冗余数据

我是python新手。我有一个文本文件，我需要避免冗余，不是通过删除，而是通过增加文本文件中的数字（如果发现行相同）

请帮忙！答案将不胜感激！ 随机文本文件的示例：

hello ram1
hello ram1
hello gate1
hello gate1

预期产出：

hello ram1
hello ram2
hello gate1
hello gate2

---

使用正则表达式和：

---

使用切片表示法、字典更新

import re

numbers = {}
with open('1.txt') as f:
    for line in f:
        row = re.split(r'(\d+)', line.strip())
        words = tuple(row[::2])  # Extract non-number parts to use it as key
        if words not in numbers:
            numbers[words] = [int(n) for n in row[1::2]]  # extract number parts.
        numbers[words] = [n+1 for n in numbers[words]]  # Increase numbers.
        row[1::2] = map(str, numbers[words])  # Assign back numbers
        print(''.join(row))

---

我打算建议使用

defaultdict（lamba:count（1））

然后使用

.format（line，next（numbers[line]））

-另外，可能不需要正则表达式-也可能是

line.rstrip（'0123456789\n'）

sufficient@falsetru很好，但是当我在中间放了一些no，它类似于：

heo.1o heo.1o

，它显示为

heo.1o1，heo.1o1

，而不是

heo.1o，heo.2o

@JonClements，

number[line]+=1

，因为默认的工厂函数只针对缺少的键调用。和

lambda:count（1）

应该是

count（1）。next

或

count（1）。\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu？（例如
he2llo wo5ld
@falsetru是的，它将包含多个数字！您能解释一下代码吗？@aseyraamsram，添加了评论。）
import re

numbers = {}
with open('1.txt') as f:
    for line in f:
        row = re.split(r'(\d+)', line.strip())
        words = tuple(row[::2])  # Extract non-number parts to use it as key
        if words not in numbers:
            numbers[words] = [int(n) for n in row[1::2]]  # extract number parts.
        numbers[words] = [n+1 for n in numbers[words]]  # Increase numbers.
        row[1::2] = map(str, numbers[words])  # Assign back numbers
        print(''.join(row))

import re

seen = {}
#open file
f = open('1.txt')
#read through file
for line in f:
    #does the line has anything?
    if len(line):
        #regex, for example, matching "(hello [space])(ram or gate)(number)"
        matched = re.match(r'(.*\s)(.*)(\d)',line)
        words = matched.group(1) #matches hello space
        key = matched.group(2) #matches anything before number
        num = int(matched.group(3)) #matches only the number

        if key in seen:
            # see if { ram or gate } exists in seen. add 1
            seen[key] = int(seen[key]) + 1
        else:
            # if { ram or gate } does not exist, create one and assign the initial number
            seen[key] = num
        print('{}{}{}'.format(words,key,seen[key]))