如何在Python中打印具有指定列宽的列表？

我有一张这样的清单

mylist = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20]

如何以指定的列宽打印列表

例如，我想打印

column=5

然后打印新行

print(mylist, column= 5)
[ 1,  2,  3,  4,  5, 
  6,  7,  8,  9, 10, 
 11, 12, 13, 14, 15, 
 16, 17, 18, 19, 20]

print(mylist, column= 10)
[ 1,  2,  3,  4,  5, 6,  7,  8,  9, 10, 
 11, 12, 13, 14, 15, 16, 17, 18, 19, 20]

或者我想打印

column=10

然后打印新行

print(mylist, column= 5)
[ 1,  2,  3,  4,  5, 
  6,  7,  8,  9, 10, 
 11, 12, 13, 14, 15, 
 16, 17, 18, 19, 20]

print(mylist, column= 10)
[ 1,  2,  3,  4,  5, 6,  7,  8,  9, 10, 
 11, 12, 13, 14, 15, 16, 17, 18, 19, 20]

---

我知道我可以使用for loop来实现这一点，但我想知道是否已经有了这样做的函数？

使用numpy数组而不是列表，并重新调整数组的形状

>>> import numpy as np
>>> array = np.array([1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20])
>>>
>>> column = 5
>>> print(array.reshape(len(array)/column, column))
[[ 1  2  3  4  5]
 [ 6  7  8  9 10]
 [11 12 13 14 15]
 [16 17 18 19 20]]
>>>>>> column = 10
>>> print(array.reshape(len(array)/column, column))
[[ 1  2  3  4  5  6  7  8  9 10]
 [11 12 13 14 15 16 17 18 19 20]]

---

当然，如果无法将

数组

划分为大小相同的

列

这将抛出一个

ValueError

。

不确定原因，但我认为可以通过将行数固定为-1，使用numpy array REFORMATE来实现我认为您想要实现的目标

import numpy as np
array=np.array([1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20]) array
array([ 1,  2,  3,  4,  5,  6,  7,  8,  9, 10, 11, 12, 13, 14, 15, 16, 17,
       18, 19, 20])
array.reshape(-1,5)

给予

array([[ 1,  2,  3,  4,  5],
       [ 6,  7,  8,  9, 10],
       [11, 12, 13, 14, 15],
       [16, 17, 18, 19, 20]])

array.reshape(-1,10)

给予

---

您也可以通过使用切片来实现这一点

mylist = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20]

def print_list(mylist, no_of_cols):
    start_index = 0
    for i in range(no_of_cols, len(mylist), no_of_cols):
        print mylist[start_index:i]
        start_index = i

    if len(mylist) > start_index:
        print mylist[start_index:len(mylist)]

print_list(mylist, 5)

---

酷，我不知道

重塑
接受-1作为参数。更多信息请点击此处：