在python中,如果单元格在数据帧中为NaN,则删除该单元格
我有一个这样的数据帧在python中,如果单元格在数据帧中为NaN,则删除该单元格,python,pandas,dataframe,data-analysis,Python,Pandas,Dataframe,Data Analysis,我有一个这样的数据帧 Project 4 Project1 Project2 Project3 0 NaN laptio AB NaN 1 NaN windows ten NaN 0 one NaN NaN 1 two NaN NaN 我想从Project 4列中删除NaN值 我期望的输出应该
Project 4 Project1 Project2 Project3
0 NaN laptio AB NaN
1 NaN windows ten NaN
0 one NaN NaN
1 two NaN NaN
我想从Project 4列中删除NaN值
我期望的输出应该是
df
如果数据帧的索引只是标准的0到n顺序整数,则可以将Project4列弹出为一个系列,删除NaN值,重置索引,然后将其与数据帧合并
import pandas a pd
df = pd.DataFrame([[pd.np.nan, 1,2,3],
[pd.np.nan, 4,5,6],
['one',7,8,9],
['two',10,11,12]], columns=['p4','p1','p2','p3'])
s = df.pop('p4')
pd.concat([df, ps.dropna().reset_index(drop=True)], axis=1)
# returns:
p1 p2 p3 p4
0 1 2 3 one
1 4 5 6 two
2 7 8 9 NaN
3 10 11 12 NaN
Project3列中的第三个NaN来自哪里?我猜有空表示的单元格包含空字符串?是的@Goyo,下面的答案对我有用。谢谢,我能用这个dropna试着用append代替concat吗
import pandas a pd
df = pd.DataFrame([[pd.np.nan, 1,2,3],
[pd.np.nan, 4,5,6],
['one',7,8,9],
['two',10,11,12]], columns=['p4','p1','p2','p3'])
s = df.pop('p4')
pd.concat([df, ps.dropna().reset_index(drop=True)], axis=1)
# returns:
p1 p2 p3 p4
0 1 2 3 one
1 4 5 6 two
2 7 8 9 NaN
3 10 11 12 NaN