Python 在tkinter中树视图中for循环的每个父节点下添加子节点
我正在尝试制作一个树视图,它显示来自mysql数据库的数据。它检索数据,并将其转换为元组列表。我已经创建了一个for循环,它很好地获取数据并将其放入树视图中Python 在tkinter中树视图中for循环的每个父节点下添加子节点,python,mysql,tkinter,treeview,ttk,Python,Mysql,Tkinter,Treeview,Ttk,我正在尝试制作一个树视图,它显示来自mysql数据库的数据。它检索数据,并将其转换为元组列表。我已经创建了一个for循环,它很好地获取数据并将其放入树视图中 count = 0 for record in rows: #forloop adding all the information from data list, no matter how many their are in the list my_tree.insert(parent='', index='end', i
count = 0
for record in rows: #forloop adding all the information from data list, no matter how many their are in the list
my_tree.insert(parent='', index='end', iid=count, text='', values=(record[0], record[1], record[2], record[3], record[4], record[5]))
count += 1
但是,在每个父节点下,我希望for循环也放置一个子节点。当前的树视图如下所示
studentid firstname lastname class1 class2 class3
0 5 Ayoung ere 23 29 22
1 6 Emma 4343 24 22 25
2 7 John 343G&$ 28 26 27
3 8 Anthony @^b 26 25 22
4 9 Enshean E(! 23 26 29
5 12 Ian %^&67HN 23 25 26
6 13 Ludwig Beethoven 23 26 29
7 14 Wolfgang Mozart 23 24 26
8 19 Joseph Haydn 23 26 27
9 20 Enshean @&V 23 26 29
10 21 Enshean L^& 23 26 29
在列表中的每个人下面都有一个子节点,该节点将显示从数据库检索的另一个列表中的3条信息。列表如下所示:
[(22, 'Math', 'Mr. Rosario', 'D2'), (23, 'Music', 'Mr. Young', 'M1'), (24, 'Biology', 'Ms. Marks', 'C4'), (25, 'Chemistry', 'Mr. Musk', 'C2'), (26, 'Physics', 'Mr. Walrath', 'A8'), (27, 'Economics', 'Mr. Sinclair', 'E12'), (28, 'DGT', 'Mr. Turing', 'F3'), (29, 'English', 'Mr. Gibson', 'B5')]
正如我们在我的树视图中看到的,在class1、2和3下有一个数字,它对应于上面所示的另一个数据库的id。我希望在子节点中的每一个类下都有一个类的名称。例如:
studentid firstname lastname class1 class2 class3
0 5 Ayoung ere 23 29 22
> Music English Math
1 6 Emma BI$! 24 22 25
> Biology Math Chemistry
很难用语言表达,但希望你能理解。如果您能帮助将带有相应数据的子节点放在for循环中的每个父节点下,我们将不胜感激。您可以将列表变成一个命令:{number:subject}。 如果您的列表被称为
rows2
,您可以
dic = {values[0]: values[1] for values in rows2}
然后将子项添加到树中
tree.insert(count, 'end', values=('',)*3 + tuple(dic[record[i]] for i in range(3,6)))
其中,count
是项目iid,记录第一个数据库中的值
完整示例
import tkinter as tk
from tkinter import ttk
root = tk.Tk()
columns = ['studentid', 'firstname', 'lastname', 'class1', 'class2', 'class3']
tree = ttk.Treeview(root, columns=columns)
for col in columns:
tree.heading(col, text=col)
tree.pack()
# first database
rows = [
[5, 'Ayoung', 'ere', 23, 29, 22],
[6, 'Emma', '4343', 24, 22, 25],
[7, 'John', '343G&$', 28, 26, 27],
[8, 'Anthony', '@^b', 26, 25, 22],
[9, 'Enshean', 'E(!', 23, 26, 29],
[12, 'Ian', '%^&67HN', 23, 25, 26],
[13, 'Ludwig', 'Beethoven', 23, 26, 29],
[14, 'Wolfgang', 'Mozart', 23, 24, 26],
[19, 'Joseph', 'Haydn', 23, 26, 27],
[20, 'Enshean', '@&V', 23, 26, 29],
[21, 'Enshean', 'L^&', 23, 26, 29]
]
# second database
rows2 = [
(22, 'Math', 'Mr. Rosario', 'D2'), (23, 'Music', 'Mr. Young', 'M1'),
(24, 'Biology', 'Ms. Marks', 'C4'), (25, 'Chemistry', 'Mr. Musk', 'C2'),
(26, 'Physics', 'Mr. Walrath', 'A8'),
(27, 'Economics', 'Mr. Sinclair', 'E12'), (28, 'DGT', 'Mr. Turing', 'F3'),
(29, 'English', 'Mr. Gibson', 'B5')
]
# dictionary from second database
dic = {values[0]: values[1] for values in rows2}
# put data in treeview
for count, record in enumerate(rows): #forloop adding all the information from data list, no matter how many their are in the list
tree.insert(parent='', index='end', iid=count, text='', values=(record[0], record[1], record[2], record[3], record[4], record[5])) # data from first database
tree.insert(count, 'end', values=('',)*3 + tuple(dic[record[i]] for i in range(3,6))) # subitem using second database
root.mainloop()
你可以把你的列表变成一个口述:{number:subject}。
如果您的列表被称为rows2
,您可以
dic = {values[0]: values[1] for values in rows2}
然后将子项添加到树中
tree.insert(count, 'end', values=('',)*3 + tuple(dic[record[i]] for i in range(3,6)))
其中,count
是项目iid,记录第一个数据库中的值
完整示例
import tkinter as tk
from tkinter import ttk
root = tk.Tk()
columns = ['studentid', 'firstname', 'lastname', 'class1', 'class2', 'class3']
tree = ttk.Treeview(root, columns=columns)
for col in columns:
tree.heading(col, text=col)
tree.pack()
# first database
rows = [
[5, 'Ayoung', 'ere', 23, 29, 22],
[6, 'Emma', '4343', 24, 22, 25],
[7, 'John', '343G&$', 28, 26, 27],
[8, 'Anthony', '@^b', 26, 25, 22],
[9, 'Enshean', 'E(!', 23, 26, 29],
[12, 'Ian', '%^&67HN', 23, 25, 26],
[13, 'Ludwig', 'Beethoven', 23, 26, 29],
[14, 'Wolfgang', 'Mozart', 23, 24, 26],
[19, 'Joseph', 'Haydn', 23, 26, 27],
[20, 'Enshean', '@&V', 23, 26, 29],
[21, 'Enshean', 'L^&', 23, 26, 29]
]
# second database
rows2 = [
(22, 'Math', 'Mr. Rosario', 'D2'), (23, 'Music', 'Mr. Young', 'M1'),
(24, 'Biology', 'Ms. Marks', 'C4'), (25, 'Chemistry', 'Mr. Musk', 'C2'),
(26, 'Physics', 'Mr. Walrath', 'A8'),
(27, 'Economics', 'Mr. Sinclair', 'E12'), (28, 'DGT', 'Mr. Turing', 'F3'),
(29, 'English', 'Mr. Gibson', 'B5')
]
# dictionary from second database
dic = {values[0]: values[1] for values in rows2}
# put data in treeview
for count, record in enumerate(rows): #forloop adding all the information from data list, no matter how many their are in the list
tree.insert(parent='', index='end', iid=count, text='', values=(record[0], record[1], record[2], record[3], record[4], record[5])) # data from first database
tree.insert(count, 'end', values=('',)*3 + tuple(dic[record[i]] for i in range(3,6))) # subitem using second database
root.mainloop()