Python Django在创建模型时出错

我在使用外来对象创建用户配置文件时遇到问题

我有一个用户，我想为该用户附加一个帐户类型

model.py

from __future__ import unicode_literals

from django.db import models
from django.contrib.auth.models import User


class UserProfile(models.Model):
    user = models.ForeignKey(User, unique=True)
    account = models.ForeignKey(Account, unique=True)

class Account(models.Model):
    reports = models.IntegerField(default=3)
    accounttype = models.CharField(default='Free', max_length=250)
    description = models.CharField(default='N/A', max_length=250)
    monthlycost = models.FloatField(default=0.0)

    def __str__(self):
        return self.user.username + " - " + self.accounttype

问题是我得到了以下错误：

account = models.ForeignKey(Account, unique=True)
NameError: name 'Account' is not defined

如何调用外键的Account类

from __future__ import unicode_literals

from django.db import models
from django.contrib.auth.models import User


class UserProfile(models.Model):
    user = models.ForeignKey(User, unique=True)
    account = models.ForeignKey("app_name.Account", unique=True)

class Account(models.Model):
    reports = models.IntegerField(default=3)
    accounttype = models.CharField(default='Free', max_length=250)
    description = models.CharField(default='N/A', max_length=250)
    monthlycost = models.FloatField(default=0.0)

    def __str__(self):
        return self.user.username + " - " + self.accounttype

---

您可以使用

“app\u name.Account”

而不是

Account

。用你的应用程序的名称替换

app\u name

。

根据John Gordon的评论，我将帐户移到了UserProfile之上，它成功了

class Account(models.Model):
    reports = models.IntegerField(default=3)
    accounttype = models.CharField(default='Free', max_length=250)
    description = models.CharField(default='N/A', max_length=250)
    monthlycost = models.FloatField(default=0.0)

    def __str__(self):
        return self.user.username + " - " + self.accounttype


class UserProfile(models.Model):
    user = models.ForeignKey(User, unique=True)
    account = models.ForeignKey(Account, unique=True)

---

谢谢大家：）

重新排列文件，以便首先声明帐户。将帐户类放在UserProfile类之上John Gordon将帐户向上移动成功了您是否尝试过执行此操作，它是否真的有效