Python—将用户可编辑字符串存储到列表中的问题

我在创建一个非常简单的程序时遇到了问题，该程序允许用户存储和编辑以列表格式查看的字符串（我几周前才开始编程）。每当我执行程序时，用户输入不会编辑字符串。这是我的代码，下面是程序当前的功能，以及修补后的功能（请注意，我没有收到任何错误）

以下是我的程序所做的

>>> ================================ RESTART ================================
>>> 
[1]hello
[2]
[3]
[4]
[5]

Which line would you like to edit?
> 1
You are now editing Line 1.
> hello world
[1]hello
[2]
[3]
[4]
[5]

Which line would you like to edit?
> 

这是我打算让我的程序做的

>>> ================================ RESTART ================================
>>> 
[1]hello
[2]
[3]
[4]
[5]

Which line would you like to edit?
> 1
You are now editing Line 1.
> hello world
[1]hello world
[2]
[3]
[4]
[5]

Which line would you like to edit?
> 

如果我需要提供更多的信息，我愿意

• 雅各布·登斯莫尔

---

这实际上是因为您在递归调用

main

，所以每次重置变量时都会这样做。您需要做的是将对

main

的递归调用替换为

while

循环。尽可能少地更改代码，看起来是这样的（假设您在3.x上，因此使用

input

）：

---

1.每次输入main（）时都（重新）定义了第1、2、3、4、5行；2.你没有使用列表，你只是使用了一堆相似命名的字符串；3.您可以将嵌套在

if

语句中的所有对

main

的调用减少到末尾的单个调用中。这很有效！谢谢我很惊讶我没有看到这个问题。

>>> ================================ RESTART ================================
>>> 
[1]hello
[2]
[3]
[4]
[5]

Which line would you like to edit?
> 1
You are now editing Line 1.
> hello world
[1]hello world
[2]
[3]
[4]
[5]

Which line would you like to edit?
> 

def main():
    line1="hello"
    line2=""
    line3=""
    line4=""
    line5=""
    while True:
        print("[1]"+line1)
        print("[2]"+line2)
        print("[3]"+line3)
        print("[4]"+line4)
        print("[5]"+line5)
        print("")
        print("Which line would you like to edit?")
        lineChoice=''
        while lineChoice not in ('1', '2', '3', '4', '5'):
            lineChoice=input("> ")
        if lineChoice=="1":
            print("You are now editing Line 1.")
            line1=input("> ")
        if lineChoice=="2":
            print("You are now editing Line 2.")
            line2=input("> ")
        if lineChoice=="3":
            print("You are now editing Line 3.")
            line3=input("> ")
        if lineChoice=="4":
            print("You are now editing Line 4.")
            line4=input("> ")
        if lineChoice=="5":
            print("You are now editing Line 5.")
            line5=input("> ")

main()