python-sql查询不返回任何内容
我的json看起来像这样-python-sql查询不返回任何内容,python,Python,我的json看起来像这样- [ { "Monitor Level":"1", "Estimate SLA (+30)":"214", "New Schedule":"", "Job Name":"\\Job1\\jobgroup", "Estimated Duration":"183", "Actual Duration":"184" }, { "Monitor Level":"1", "Estimate SLA (+3
[
{
"Monitor Level":"1",
"Estimate SLA (+30)":"214",
"New Schedule":"",
"Job Name":"\\Job1\\jobgroup",
"Estimated Duration":"183",
"Actual Duration":"184"
},
{
"Monitor Level":"1",
"Estimate SLA (+30)":"179",
"New Schedule":"8:00 PM",
"Job Name":"\\Job2\\jobgroup",
"Estimated Duration":"1349",
"Actual Duration":"1349"
}
]
我运行以下代码-
for o in json_object:
# get jobid
db = pyodbc.connect('DRIVER={SQL Server};SERVER=dvidbsql01\dev2008;DATABASE=Admiral;UID=Tidal;PWD=tidal97')
cur = db.cursor()
cur.execute("""select jobmst_id from jobmst where jobmst_prntname + '\\' + jobmst_name = ?""", o['Job Name'])
r= cur.fetchall()
print r
并且r
返回我想要的值
如果我使用代码,我想-
sql_jobid = """
select jobmst_id 'Job ID' from jobmst where jobmst_prntname + '\\' + jobmst_name = ?
"""
## DEFINE ENVIRONMENT DATABASES
def db():
if args.environment == 'DEV':
return pyodbc.connect('DRIVER={SQL Server};SERVER=server\instance;DATABASE=db;UID=user;PWD=pass')
## DEFINE UPDATE
def query_db(query, args=(), one=False):
cur = db().cursor()
cur.execute(query, args)
r = [dict((cur.description[i][0], value) \
for i, value in enumerate(row)) for row in cur.fetchall()]
cur.connection.close()
return (r[0] if r else None) if one else r
for o in json_object:
# get jobid
jobid = query_db(sql_jobid, (o['Job Name'][0]))
print jobid
它不是打印我想要的值,即使它正在做同样的事情。即使将o['Job Name'][0]
替换为'Job1\jobgroup'
也不会返回任何内容,因此我的pythonic代码似乎不想解析作业名称。在下一行中
jobid = query_db(sql_jobid, (o['Job Name'][0]))
(o['Job Name'][0])
不是元组。如果要传递元组,则需要附加一个尾随逗号
jobid = query_db(sql_jobid, (o['Job Name'][0],))
# ^
谢谢你给我指明了正确的方向!这不完全是。我不需要逗号,但我也不需要[0]@因为
o['Job Name']
本身是一种序列对象?o['Job Name']在json文件中返回一个值。