Python 列出给定数字集合的组合及其总数

我使用这段代码从一组给定的列表中生成三个数字的组合

import itertools

thelist = [0, 0, 0, 1, 1, 2, 2, 1]
for L in range(3,4):
    for subset in itertools.combinations(thelist, L):
        print(subset)

这很好，结果如下所示：

(0, 0, 0)
(0, 0, 1)
(0, 0, 1)
(0, 0, 2)
(0, 0, 2)
(0, 0, 1)
(0, 0, 1)
(0, 0, 1)
(0, 0, 2)
(0, 0, 2)
(0, 0, 1)
(0, 1, 1)
(0, 1, 2)
(0, 1, 2)
(0, 1, 1)
(0, 1, 2)
(0, 1, 2)
(0, 1, 1)

(0, 0, 0) =>0
(0, 0, 1) =>1
(0, 0, 1) =>1
(0, 0, 2) =>2
(0, 0, 2) =>2
(0, 0, 1) =>1
(0, 0, 1) =>1
(0, 0, 1) =>1
(0, 0, 2) =>2
(0, 0, 2) =>2
(0, 0, 1) =>1
(0, 1, 1) =>2

我想列出生产组合的总和。我该怎么做？ 因此，输出将如下所示：

(0, 0, 0)
(0, 0, 1)
(0, 0, 1)
(0, 0, 2)
(0, 0, 2)
(0, 0, 1)
(0, 0, 1)
(0, 0, 1)
(0, 0, 2)
(0, 0, 2)
(0, 0, 1)
(0, 1, 1)
(0, 1, 2)
(0, 1, 2)
(0, 1, 1)
(0, 1, 2)
(0, 1, 2)
(0, 1, 1)

(0, 0, 0) =>0
(0, 0, 1) =>1
(0, 0, 1) =>1
(0, 0, 2) =>2
(0, 0, 2) =>2
(0, 0, 1) =>1
(0, 0, 1) =>1
(0, 0, 1) =>1
(0, 0, 2) =>2
(0, 0, 2) =>2
(0, 0, 1) =>1
(0, 1, 1) =>2

---

如果您只是在python

=3.6

中打印，则可以使用f字符串，只需执行以下操作：

import itertools

thelist = [0, 0, 0, 1, 1, 2, 2, 1]
for L in range(3,4):
    for subset in itertools.combinations(thelist, L):
        print(f"{subset} => {sum(subset)}")

---

对于Python

，如果您只是在Python
=3.6
中打印，则可以使用f字符串，只需执行以下操作：

import itertools

thelist = [0, 0, 0, 1, 1, 2, 2, 1]
for L in range(3,4):
    for subset in itertools.combinations(thelist, L):
        print(f"{subset} => {sum(subset)}")

对于Python